Complete a Verilog code for a 4-bit one-hot counter. Complete "your code here" boxes below (two parts). The "reset" is an active HIGH and will asynchronously_make the output to 4'b1000. 1000 0100 → 0010 → 0001 1000 > .... repeat!! module four bit_ohc (clk, reset, q); output [3:0] q; input clk, reset; // your code here always @(posedge clk, reset) begin // your code here end endmodule

Someone is providing wrong code, it is giving wrong output for the below code. Request you please provide right code num_inputs = int(input()) for i in range(num_inputs): n = int(input()) for j in range(n, 0, -1): for k in range(j, 0, -1): print(k, end=' ') print() 4→ Write a python program with a screenshot output in google collab by taking input from the keyboard Write a program that reads an input n from stdin. n tells us the number of rows to be printed. Print the pattern as per the given examples. Input format: The first line contains the number of inputs. The lines after that contain a different value for n Example Input: 2 3 5 Output 3 3 2 3 2 1 5 5 4 5 4 3 5 4 3 2 5 4 3 2 1

write a code that decodes the coloured bands on a resistor.Each colour band printed on a resistor has a corresponding numeric value, as shown in the table below: Colour Numeric value black 0 brown 1 red 2 orange 3 yellow 4 green 5 blue 6 violet 7 grey 8 white 9 To calculate the total resistance value, the following formula should be used: resistance=(10a+b)⋅10^c where a, b, and c are the numeric values of the first, second, and third colour bands respectively. For example, let's say that the colour bands on a resistor are red-green-orange. In this case, a=2, b=5, and c=3 (using the table). Hence the resistance value is 25000 ohms: resistance=(10*2+5)⋅10^3=25000 ohms Your task is to write a program which asks the user to input the three colour bands. The program should then calculate and output the resistance value indicated by the bands. As part of your solution, you must define and use a function named colour_to_number. This function should take one…

I get an error in LC3 assembly programming when i try to run this code. can someone explain how i can fix this and give me the solution to the fix. i will be very thankfull

In the following code, the first printf() reached produces the output “14,” but the second printf() can cause a bus error or a segmentation fault. Why? main(){ int *p;funct(p);printf("%d\n",*p);}funct(int *p2){p2=(int *)malloc(4);*p2=14;printf("%d\n",*p2);}

c program that runs in turbo c only (Use do-while loop statement) Write a program which produces the given sequence nos. (in alternate arrangement) using: Sample input/output dialogue: Enter limit: 10 Result is: 10 2 9 4 8 6 7 8 6 10 5 12 4 14 3 16 2 18 1 20

Based on the Tinkercad circuit accessible from the link below, complete the following activities:https://www.tinkercad.com/things/c1qtxCkOuBW   Code is, // C++ code// const byte LED_PIN = 13;const byte METER_PIN = A4; void setup(){  pinMode(LED_PIN, OUTPUT);  pinMode(METER_PIN, INPUT);        Serial.begin(9600);    startTimer();} void loop(){ }   void startTimer(){  noInterrupts();        interrupts();} ISR(TIMER1_COMPA_vect){   digitalWrite(LED_PIN, digitalRead(LED_PIN) ^ 1);}   1. Complete the code in a way that LED blinks every 2 seconds.2. Change the startTimer method to accept a double value called timerFrequency, which representsthe frequency of the timer. Change the startTimer function so that it uses the value of this parameterto calculate and set the correct values for the OCRx and TCCRx registers.3. Use the potentiometer sensor connect to pin A4 to enable users to configure the timer frequency. Plsease share the final code only.