Compare ceramics to metals and polymers respectively in terms of deformation
Q: property of a material if, after being loaded, the material returns to its original shape when the…
A: Given
Q: A cylindrical aluminum alloy rod with a 0.5 in. diameter is subjected to ten- sion. Determine the…
A: Diameter of rod, d = 0.5 in Change in diameter, ∆d = -10-4 in Young’s modulus, E = 11x106 psi…
Q: The modulus of elasticity of 30mm diameter aluminum bar was 80 Gpa, calculate the strain and the…
A:
Q: 1 The material deforms considerably even with a slight increase in stress. Yielding b. Fracture a.…
A: The property of material can be explained as follows- Yield point- It is the point in the…
Q: A steel alloy bar 100 mm long with a rectangular cross section of 10 mm X 40 mm is subjected to…
A: Concept: Since it has been given that the material is linearly elastic within applied load, the…
Q: The graphs in figure 5 show how tensile stress varies with tensile strain for two metallic wires…
A: Breaking stress : It is the maximum stress at which a material can take before it fails. For copper…
Q: Why Ceramics are stronger in compression than in tension
A: The properties of ceramic Material: Ceramics is a rigid and brittle material and is not capable…
Q: A cylindrical specimen of a hypothetical metal alloy is stressed in compression. If its original…
A: nE=2G1+μ105239.7=1+μμ=0.322εd=δdd=0.026220εd=1.31×10-3εh=δhh=h-74.96h
Q: Which among the following is the structural deformation measured in torsion-loaded bodies? Change in…
A: Torsional shearing stress Torque Bending Angle of twist
Q: What are the advantages and disadvantages of hot deformation as compared to cold deformation
A: Hot and cold deformation of steel is don't to manufacture and give shapes to the steel.
Q: Materials can have different masses but equal volumes. a. TRUE b. FALSE
A: Density : It is the ratio of mass and volume . Mass : it defines about how much matter an object…
Q: With the help of a diagram, contrast the stress-strain relationship with respect to ceramic and…
A: Metals are usually hard, opaque, shiny, and have sensible electrical and thermal conductivity.…
Q: Question 15 materials are materials that can be drawn out under tension without fracture. O Ductile…
A: We have to know which materials can be drawn out under tension without failure...
Q: A aluminum plate 0.5 cm thick is to withstand a force of 50,000 N with no permanent deformation. If…
A: Given Data: The thickness of the plate is t=0.5 cm The force to be withstand by the plate is F=50000…
Q: A) A specimen of alloy having the following engineering stresses produces the corresponding plastic…
A: Given :- To find :- Engineering stress corresponding to engineering strain of 0.4
Q: A tensile force of 5 kN produce an elastic reduction in diameter of 4 x 10-4 mm on a metal alloy…
A: given data: Force (F)=5 KNdiameter (d)=6 mmreduction in diameter(∆d)=4×10-4 mm
Q: This is a mechanical property of engineering materials that exhibits a slow deformation under long…
A: given - mcq to find -mechanical property of engineering materials that exhibits a slow deformation…
Q: The deformation per unit of the original length of a material is called as a. Stress O b. Strain O…
A:
Q: A) A specimen of alloy having the following engineering stresses produces the corresponding plastic…
A: Given above table and we have to find the engineering stress which produces engineering strain of…
Q: A tensile force of 5 kN produce an elastic reduction in diameter of 4 x 10-4 mm on a metal alloy…
A:
Q: A body in which the deformation is negligible is called a. Rigid body b. Deformable body O c.…
A: Non-deformable body: The body which doesn't under deformation during the application of the load on…
Q: Elastic deformation, Ductile deformation and Permanent stage are the three stages of deformation…
A: True only We know that the material which is subjected to external loads then it will Start…
Q: A steel rod of length = 3m, diameter - 300 mm and modulus of elasticity = 200 GPa is inserted into…
A:
Q: 1. The following question has two parts, answer BOTH parts. (a) On the basis of miero-structural…
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Q: Time l Which of the following is associated with minimum plastic deformation? O a. Ductile fracture…
A: Answer :- Option b Brittle fracture In a brittle fracture, the amount of plastic deformation in…
Q: Five classes of ceramic materials have been defined.
A: Ceramics is crystalline or partly crystalline in structure. These ceramics are made of inorganic,…
Q: Q-5 Consider an S-590 alloy component as shown in following figure that is subjected to a stress of…
A: Solution: Given data: stress=200 Mpa
Q: accuracy and precision
A: Accuracy It is defined as the degree of closeness of observations to the true value or in other…
Q: A tensile force of 1.5kN produce an elastic reduction in diameter of 3.6 x 104 mm on a metal alloy…
A: We know, and
Q: len A material has the stress-strain behavior shown in the Figure below. Calculate the toughness (T)…
A:
Q: A cylindrical aluminum alloy rod with a 0.5 in. diameter is subjected to ten- sion. Determine the…
A:
Q: An aluminum alloy cylindrical bar of 10 mm diameter is subjected to 5 kN tensile load which reduces…
A: Given: Initial diameter, d = 10 mm Tensile load, P = 5 kN Final diameter, d’ = 9.997 mm Young’s…
Q: effect of crosslinks on an elastomer
A: Elastomers are loosely cross-linked polymers. They have the characteristics of rubber in terms of…
Q: explain why ceramics are stronger and stiffer than polymers
A: Ceramic is more stronger and stiffer than polymer Explanation points are mentioned below -
Q: Piano strings are made of a fibre which is pulled taut. When the string is tapped in the centre by a…
A: Given, e = 0.2% σ = 100 MPa
Q: The stress-strain diagram for a metal alloy having an original diameter of 16 mm and a gauge length…
A: In this question , We calculate approximately Elastic modulus , yielding load and ultimate load…
Q: Determine the percentage of ductility of a metal alloy having the following tensile stress-strain…
A: From the given tensile stress-strain diagram of a metal alloy, The strain at limit of…
Q: Value of one of the properties of A36 steel plate within the limit of its elasticity
A: Mechanical Properties Imperial Metric Ultimate Tensile Strength 58,000 – 79,800 psi 400 – 550 MPa…
Q: Difference between strength, hardness and toughness of a material
A: Strength: This is the ability of material which is required to maintain it's shape from force which…
Q: An aluminum rod of length 100 mm and diameter 15 mm is subjected to a normal load of 10 kN. The new…
A: Introduction- Shear stress occurs when a force operates parallel to an object's surface. Consider a…
Q: Which materials tend to exhibit elastic perfectly plastic behavior?
A: The shape of some material gets changed when energy goes in and this phenomena is known as plastic…
Q: Why Ceramics are stronger in compression than in tension? (Provided that the answer is scientific…
A:
Q: A material has modus of rigidity 250 GN/ m and bulk modulus of 450 GN/mm. What will be the value of…
A: given- modulus of rigidity G=250 GN/mm2bulk modulus of k = 450 GN/mm2
Q: A steel alloy bar 100 mm long with a rectangular cross section of is subjected to tension with a…
A: The given data is as follows: Length of steel alloy bar=100 mmRectangular cross-section=10 mm×40…
Q: A tensile force of 5 kN produce an elastic reduction in diameter of 4 x 10-4 mm on a metal alloy…
A:
Q: (i) Write down the breaking tensile stress of each of the materials. (ii) Which of the materials is…
A: Draw the figure.
Q: A cylindrical specimen of undeformed brass that has a diameter of 300 mm is elastically deformed to…
A:
Q: The material returns to its original shape when the load is removed. (A Elastic Limit B Elastic…
A: Given data in question Stress strain behavior To find out When will the material returns to its…
Compare ceramics to metals and polymers respectively in terms of deformation
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- Explain in detail the effect of Temperature on the Elastic Modulus and Yield Strength ofEngineering materials.With the help of a diagram, contrast the stress-strain relationship with respect to ceramic and metalsWith the help of a diagram, contrast the stress-strain relationship with respect to ceramic and metalsMechanics of materials involves two main activities: design and analysis of structures. Match the most appropriate activity with the result. determining the member stress determine the member dimensions
- The deformation per unit of the original length of a material is called as O a. Stress b. Strain c. Young's Modulus d. Modulus of ElasticityPermanent deformations in structures refer to: A. linear elastic deformations B. deflection diagram C. linear inelastic deformation D. plastic deformationThe following figure shows the tensile stress-strain curve for a plain-carbon steel. 600 80 500 MPa 600 10 psi 60 80 400 400 60- 300 40 40 200 200 20 20 100 0.005 0.05 0.10 0.15 Strain (a) What is this alloy's tensile strength? MPа (b) What is its modulus of elasticity? GPa (c) What is the yield strength? i MPa Stress (MPa) Stress (10 psi)
- 1. The tensile strength vs. temperature curves of aluminum are plotted below. Explain the meaning of these two curves. 400 Ultimate strength 300 Yield strength 200 100 -200 -150 -100 -50 50 100 150 200 250 Temperature, °C Strength, kPaThe strength-to-weight ratio of a structuralmaterial is defined as its load-carrying capacitydivided by its weight. For materials in tension, usea characteristic tensile stress obtained from a stressstraincurve as a measure of strength. For instance,either the yield stress or the ultimate stress could beused, depending upon the particular application.Thus, the strength-to-weight ratio RS/W for a materialin tension is defined as RS/W =σ/γ in which σ is the characteristic stress and γ is theweight density. Note that the ratio has units of length. Using the ultimate stress sU as the strength parameter,calculate the strength-to-weight ratio (in unitsof meters) for each of the following materials: aluminumalloy 6061-T6, Douglas fir (in bending), nylon,structural steel ASTM-A572, and a titanium alloy.Obtain the material properties from Tables I-1 andI-3 of Appendix I. When a range of values is given ina table, use the average value.Consider the 1040 carbon steel listed in the textbook's Table 6.1: A 20mm-diameter bar of this alloy is used as a structural member in an engineering design. The unstressed length of the bar is precisely 1m. The structural load on the bar is 1.2×10^5N in tension. What will be the length of the bar under this structural load (in meters)? Values from table: E [GPa (psi)] = 200(29*10^6) Y.S [MPa (ksi)] = 600(87) T.S [MPa (ksi)] = 750(109) Percent Elongation at failure = 17