Compare and interpret the infrared spectra of 4-methylcyclohexene and 4-methylcyclohexanol.

Aldehydes and ketones react with one molecule of an alcohol to form compounds called hemiacetals, in which there is one hydroxyl group and one ether-like group. Reaction of a hemiacetal with a second molecule of alcohol gives an acetal and a molecule of water. We study this reaction in Chapter 16. Draw structural formulas for the hemiacetal and acetal formed from these reagents. The stoichiometry of each reaction is given in the problem.

Write the common (not IUPAC) name and standard abbreviation for each molecule. o 9=8-0 O-CH, H O=d-0 H H O=d-0 OH H انه H O-CHO H 9 H H OH H N Fo H H OH H H NH NH NH₂ H NH₂ Name: 0 Abbreviation: 0 Name: 1 Abbreviation: 0 Name: 0 Abbreviation: 0

Write down the common (not IUPAC) names of the organic molecules that would be released if this molecule were hydrolyzed: CH2−O−C—(CH2);–CH=CH–CH2–CH=CH—(CH2)4—CH3 CH-O-C-(CH2)14-CH3 O 11 CH2−O−C— (CH2)14 — CH3 Separate each name with a comma. You will find useful information in the ALEKS Data resource. 1 010 Continue O a X 000 Y F8 F9 Submi

explain why methanethiol, CH3SH, has a lower boiling point (6°C) than methanol, CH3OH (65°C), even though methanethiol has a higher molecular weight

CH3 CH3 CH-CH-CH-CH-COOH Part 2 of 3 Part 2 of 3 X S CH3-CH-CH2-CH2-COOH Cl Part 3 of 3 Part 3 of 3 G ง Part 2 of 3 Part 3 of 3 OH -CO₂-CH2-CH2-CH2-CH Give the IUPAC name for each structure. Part 1 of 3 CH,(CH,),CO,(CH,),CH, 5

Show how to convert cyclohexanol to these compounds. a. Cyclohexene b. Cyclohexane c. Cyclohexanone d. Bromocyclohexane

Both 1,2-dihydronaphthalene and 1,4-dihydronaphthalene may be selectively hydrogenated to 1,2,3,4-tetrahydronaphthalene.One of these isomers has a heat of hydrogenation of 101 kJ/mol (24.1 kcal/mol), and the heat of hydrogenation of the other is 113 kJ/mol (27.1 kcal/mol). Match the heat of hydrogenation with the appropriate dihydronaphthalene.

Give the IUPAC name for each compound.

Why is the boiling point of propane-1,3-diol (HOCH2CH2CH2OH) higher than the boiling point of propane-1,2-diol [HOCH2CH(OH)CH3] (215 °C vs. 187 °C)? Why do both diols have a higher boiling point than butan-1-ol (CH3CH2CH2CH2OH, 118 °C)?