Combining 0.229 mol Fe2O30.229 mol Fe2O3 with excess carbon produced 13.0 g Fe.13.0 g Fe.   Fe2O3+3C⟶2Fe+3COFe2O3+3C⟶2Fe+3CO   What is the actual yield of iron in moles? actual yield:     What is the theoretical yield of iron in moles? theoretical yield:     What is the percent yield? percent yield:      %

iewiorm 18. Reacting 8.85 g of SiO2 with excess carbon produces 2.25g of SiC. What is the percent yield? SiO2 + 3C--> SiC + 2CO* 90% 45% 82% 38% 19. In question number 18, what was the limiting reactant? * C SiC CO Si02

urces xGveUp Hint Combining 0.342 mol Fe,O, with excess carbon produced 11.2 g Fe. Fe,0, + 3C – 2 Fe + 3 CO What is the actual yield of iron in moles? actual yield: mol What is the theoretical yield of iron in moles? mol theoretical yield: What is the percent yield? % percent yield: 63 F Sunny A ô

Combustion of 8.45 mg of an unknown substance yields 14.0 mg CO2 and 7.08 mg H2O. The unknown substance contains only C, H, and O. What is the percentage of each element in this substance? Percentage of C = Percentage of H = % Percentage of O =

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For the given chemical reaction given, how many moles of sodium sulfate will be produced from 28.1 g of sodium hydroxide?

Percent yield. 4Fe + 3O2 ---> 2Fe2 O3 Starting with 320g of oxygen gas you produce 75g of Iron(iii) oxide. What is the percent yield?

Combining 0.277 mol Fe2O30  with excess carbon produced 10.0 g.   Fe2O3+3C⟶2Fe+3CO   What is the actual yield of iron in moles? actual yield:   What is the theoretical yield of iron in moles? theoretical yield:   What is the percent yield? percent yield:   %

In this reaction: 4Fe (s) + 30₂ (g) 2 2Fe203 (s) If 2.34 moles of Fe reacts with 4.53 moles of O2, and 0.95 moles of Fe2O3 form, what is the percent yield? %

How many moles of each reactant are needed to produce 4.00 moles of HF? 2NH3(g) + 5F2(g) —> N2F4(g) + 6HF(g)