Color blindness is a sex linked disease (on the X chromosome). The recessive form of t will lead to the disease. A woman who is a carrier for color blindness marries a color blind man. Draw genetic chart to show their off springs with thecir phenotypes (color blind or not), genotypes and sex of the children, State clearly generations of P and F1.
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- Proband Sex-linked Brackets Arabic numerals Heterosis ||| E III III E III ||| Depict the birth order in a generation of offspring. The first time the condition being studied is recorded but not necessarily the first time the condition has occurred. Unusual vigor or increased function of an organism in a heterozygous state. Genes located on a sex chromosome result in sexually dependent inheritance of certain traits. Placed around a gender symbol such as a circle or square or diamond to indicate adoption. Open in Reading VIn individuals affected by cystic fibrosis, salt crystals may appear afterperspiration dries up. In addition, the disease causes respiratory disorderswhich can be both debilitating and lethal. It occurs in individuals homozygousfor recessive gene. If 2 normal parents had a daughter with the symptoms ofthis disease, and a normal son, what is the probability that he might be acarrier of the recessive gene?Express answer in fraction form.In this case a family history revealed a genetic basis for the disorder. The pedigree is shown in Fig. 1 Below. Key Ø Female: affected Female: unaffected || IV V 5600 orize 077808 15 10 9 10 CHO વ Male: affected Male: unaffected Deceased Disease status not given Dizygotic twins Monozygotic twins Fig. 1 Disease pedigree. Five generations I, II, III, IV, V are shown. Females are represented by circles, males by squares, dizygotic (non-identical) twins by diagonal lines originating from the same point, Monozygotic (identical) twins by diagonal lines originating from the same point and joined symbols and deceased by a diagonal line through the symbol. Filled symbols indicate that the individual displays the disease phenotype. Unfilled symbols indicate that the individual does not display the disease phenotype. Carriers of the disease are not indicated. Information on disease status is not known for generation I and is omitted for the individuals represented by a symbol with an asterisk.…
- A C In the image above, the tissue found at letter B is; Нaploid Diploid Neither B.Which of the Pedigree Diagrams below is most likely to show a family with Hereditary haemorrhagic telangiectasia? A Affected female Normal female Atfected mate ormal male KEY Homozygous Homazygous Heterozygous Heterazygous Wild Type Male Wild Type Female Male Female Female Mala Note: Completely red symbol denotes an individual exhibiting the phenotype of interest C 3 12 1/2 IV 14 14 Affected 12 12 Known camerIn a paternity case, a single mother claimed that a certain man was the father of her baby. The man denied it claiming that her current boyfriend was the father. The court ordered a blood test (cheaper than DNA testing) to see if he could be ruled out as the father. The mother was Type O and the baby was Type O. The man was Type AB. What is the possible genotype of the biological father? heterozygous Type A homozygous Type A heterozygous Type B
- Albinism is a recessive autosomal trait for skin pigmentation. Hemophilia is a sex-linked recessivedisorder of the blood. assign alleles to the traitsA – normal skin pigmentation X H – normal blooda – albino X h - hemophilia A double heterozygous woman marries a non-hemophilic man and heterozygous for skinpigmentation. Double heterozygous means heterozygous for both traits. Aa for skin pigmentation andX H X h for blood trait. Therefore, the genotype of the woman is AaX H X h . Non-hemophilic man is X H Y and heterozygous for skin pigmentation is Aa. The genotype,therefore, of the man is AaX H Y. What is the probability that they will have:a. a child with normal skin? _____________________b. a child with normal blood? _____________________c. an albino girl? _____________________d. A hemophilic boy? _____________________a. The ability to taste the chemical phenylthiocarbamideis an autosomal dominant phenotype, and the inabilityto taste it is recessive. If a taster woman with a nontasterfather marries a taster man who in a previous marriagehad a nontaster daughter, what is the probability thattheir first child will be(1) A nontaster girl(2) A taster girl(3) A taster boyb. What is the probability that their first two childrenwill be tasters of either sex?3 10 11 12 13 14 15 16 18 19 20 21 22 Y Is this karyotype male or female? Kind of error (if any). Name of Syndrome
- The most common form of colorblindness is a recessive, sex-linked hereditary con dition caused by a defect on the X chromosome. Females are XX, while males are XY. Individuals inherit one chromosome from each parent, with equal probability; for example, an individual has a 50% chance of inheriting their father's X chromosome, and a 50% chance of inheriting their father's Y chromosome. If a male has an X chromosome with the defect, he is colorblind. However, a female with only one defective X chromo some will not be colorblind. Thus, colorblindness is more common in males than females; 7% of males are colorblind but only 0.5% of females are colorblind. (a) Assume that the X chromosome with the wild-type allele is X+ and the one with the disease allele is X. What is the expected frequency of each possible female genotype: X+X+, X+X¯, and X-X-? What is the expected frequency of each possible male genotype: X+ Y and X-Y? (b) Suppose that two parents are not colorblind. What is the…(a) Enter the parent phenotypes and complete the Punnett square Inheritance of sex linked recessive tralts Example: Hemophilia Female paront phenotype Inheritance of hemophilia is sex linked. Males with the recessive (hemophilia) allele, are affected. Females can be carriers. (normal female) Xxh (carrier female) ben-N werxhxh (hemophiliac female) leizobXY (normal male) xhy (hemophiliac male) Male parent phenotype: Using the codes: XX eggs (a) Enter the parent phenotypes and complete the Punnett square for a cross between a normal male and a carrier female. sperm (b) Give the ratios for the phenotypes from this cross. Phenotype ratios: Inheritance of sex linked dominant traits Example: Sex linked form of rickets A rare form of rickets is inherited on the X chromosome. Using the codes: XX Female parent phenotype: alvo eo (normal female); XY (normal male) (affected heterozygote female) XRXR (affected female) XRY Male parent phenotype: XRX eggs (affected male) Nor a cross between an…The maternal-effect mutation bicoid (bcd) is recessive. Inthe absence of the bicoid protein product, embryogenesis isnot completed. Consider a cross between a female heterozygousfor the bicoid mutation (bcd+/ bcd-) and a homozygousmale(bcd-/ bcd-). Predict the outcome (normal vs. failed embryogenesis) inthe F1 and F2 generations of the cross described.