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Code: //solve using camer's rule //x+y-z = 6 //3x2у+z--5 //X+3y-2z=14 а-[1,1,-1;3,-2,1%;1,3,-2;] disp(a,"enter the coefficient matrix") b=[6,-5,14] disp(b,"enter the constant matrix") d=det(a) dl=det([b,a(:,3),a(:.1)]) d2=det([b,a(:,1),a(:.1)]) d3=det([b,a(:,1),a(:.3)]) disp("solution for the algebraic equation are") x=d1/d disp(x,"the value of x is") У-d2/d disp(y,"the value of y is") z=d3/d disp(z,"the value of z is")

Code: //solve using camer's rule //x+y-z = 6 //3x2у+z--5 //X+3y-2z=14 а-[1,1,-1;3,-2,1%;1,3,-2;] disp(a,"enter the coefficient matrix") b=[6,-5,14] disp(b,"enter the constant matrix") d=det(a) dl=det([b,a(:,3),a(:.1)]) d2=det([b,a(:,1),a(:.1)]) d3=det([b,a(:,1),a(:.3)]) disp("solution for the algebraic equation are") x=d1/d disp(x,"the value of x is") У-d2/d disp(y,"the value of y is") z=d3/d disp(z,"the value of z is")

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Convert in scinotes and Display the result

Code: //solve using camer's rule //x+y-z = 6 //3x-2y+z=-5 //X+3y-2z=14 a=[1,1,-1;3,-2,1;1,3,-2;] disp(a,"enter the coefficient matrix") b=[6,-5,14] disp(b,"enter the constant matrix") d=det(a) d1=det([b,a(:,3),a(:.1)]) d2=det([b,a(:,1),a(:.1)]) d3=det([b,a(:,1),a(:.3)]) disp("solution for the algebraic equation are") x=d1/d disp(x,"the value of x is") y=d2/d disp(y,"the value of y is") z=d3/d disp(z,"the value of z is")
Transcribed Image Text:Code: //solve using camer's rule //x+y-z = 6 //3x-2y+z=-5 //X+3y-2z=14 a=[1,1,-1;3,-2,1;1,3,-2;] disp(a,"enter the coefficient matrix") b=[6,-5,14] disp(b,"enter the constant matrix") d=det(a) d1=det([b,a(:,3),a(:.1)]) d2=det([b,a(:,1),a(:.1)]) d3=det([b,a(:,1),a(:.3)]) disp("solution for the algebraic equation are") x=d1/d disp(x,"the value of x is") y=d2/d disp(y,"the value of y is") z=d3/d disp(z,"the value of z is")
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