Classify the substance shown in the sketch below. You can click the other tabs in the sketch to get a magnified view. Be sure you check all the boxes on the right-hand side that are correct for this substance. Note for advanced students: in some sketches the distance between particles has been exaggerated to make it easier to see each individual particle. classification substance (check all that apply) normal 1000X 10,000,000X Ogas liquid Osolid Oelement Ocompound Omixture Osolution Opure substance Ohomogeneous mixture Oheterogeneous mixture

Classify the substance shown in the sketch below. You can click the other tabs in the sketch to get a magnified view. Be sure you check all the boxes on the right-hand side that are correct for this substance. Note for advanced students: in some sketches the distance between particles has been exaggerated to make it easier to see each individual particle. classification substance (check all that apply) normal 1000X 10,000,000X Ogas liquid Osolid Oelement Ocompound Omixture Osolution Opure substance Ohomogeneous mixture Oheterogeneous mixture

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A tiny sample of gold contains 1.5 x 10^16 atoms.The mass of the gold sample is ______ μg.
The natural abundances and isotopic masses of the element neon (Ne) areIsotope % Abundance Isotopic Mass20Ne 90.00 19.9921221Ne 0.27 20.9931622Ne 9.73 21.99132Calculate the atomic mass of naturally occurring neon.
All samples of a given compound, regardless of their source or how they were prepared, have the same proportions of their constituent elements. Which law does this refer to? O First Law of Thermodynamics O Law of Modern Atomic Theory Law of the Conservation of Mass O Law of Multiple Proportions O Law of Definite Proportions
Matter Survey The purpose of this survey is to find out how much you already know about basic chemistry (you may surprise yourself!). Do your best! You will get full points just for submitting this survey, regardless of how well you do on it. Part 1: Vocabulary Define the following terms: (from what you remember from middle school) Matter: Atom: Molecule: Refer to a Periodic Table as needed for the questions in Parts 2-4 Part 2: Interpreting the Periodic Table 1. Give the names of the elements that correspond to the following elemental symbols: Be: Ge: 2. Give the elemental symbols that correspond to the following elements: Carbon: Copper Magnesiu m: 3. The following elements – fluorine, chlorine and bromine – are in the same (Pick one of these choices: group, period, energy level or all of the above) Part 3: Atomic Structure 1. What is the atomic mass of the following elements Calcium: Boron: Chlorine
Atomic weights are not provided, but please use rounded-off values to the nearest whole number.(examples: 24.305, use "24"; 107.8682, use "108"; 1.00784, use "1"; 15.999, use "16") Add trailing zeros to complete your answer to the 3rd decimal place, if necessary. (examples: if your answer is "62.7", write it as 62.700; if your answer is "37.12", write it as 37.120if your answer is "123", write it as 123.000) 1. A 3.50-gram sample of Streptomycin powder was tested for its water content. If the water equivalence factor of the KF reagent was 4.6, what is the percentage water content of the sample if 9.2 ml of the KF reagent was used? 2. An analyst accurately weighed 5.351 grams of sample for ash-insoluble content using the dry method. The weight of the crucible containing the ash was 40.722 grams. If the sample was said to have 2.150% of insoluble ash, what is the weight of the tared crucible?
The radius of a uranium atom is 149 pm. How many uranium atoms would have to be laid side by side to span a distance of 1.30 mm? atoms
What is the mass in grams of 8.91 × 1016 chromium atoms? Put your answer in box in scientific notation with one past the decimal in this format xx'10^-X
An element, Spencerecium, has two isotopes. Spencerecium-145 has a relative abundance of 85 % and Spencerecium-140 has a relative abundance of 15 %. What is the average atomic mass of Spencerecium? Include two decimal places in your answer.
A sample of lithium consists of 400 atoms. 30 atoms are the isotope Lithium-6 (6.015 amu) and 370 are Lithium-7 (7.016 amu). Which student correctly calculated the correct average atomic mass and why? Student 1 calculated the average atomic mass as 6.94 amu. Student 1 determined the percent abundance for each isotope and then multiplied the percent abundance by the average atomic mass of its isotope and took the sum. Student 2 calculated the average atomic mass as 6.52 amu. Student 2 took the average of the mass of the two isotopes of lithium. Student 3 calculated the average atomic mass as 1.06 amu. Student 3 took the sum of the average atomic masses of the isotopes and multiplied by the ratio of lithium-6 to lithium-7. Student 4 calculated the average mass as 13.0 amu. Student 4 added the mass of the two isotopes.
11. Identify as true (T) or false (F): Minerals separating from flowing water as stony deposits represents a physical change. A pure substance may be made of a single element or of a single compound. Atoms of different elements must have different numbers of protons in their nuclei. The smallest piece we can separate from an atomic substance physically is an atom.
A new (imaginary) element has been discovered. It exists in three naturally occurring isotopic forms. ISOTOPE Mass (amu) Abundance (%) Isotope 1 300.696 17.872 Isotope 2 302.757 20.185 Isotope 3 305.735 61.943 Calculate the mass for the element as it would appear in the periodic table. Report your answer to two decimal places.Answer
Following the ideas above, show that this data illustrates the law of multiple proportions. (Compare the masses of bromine that react with 1.00 g of gold). Two compounds of gold and bromine have these percent compositions: Compound X is 45.11% Au and 54.89% Br, Compound Y is 71.14% Au and 28.86% Br