class Main public static void main(Stringt) args) ( String[] words - ( "Ruby", "C", "Python", "Java" }; for (int i 0; 1 < 3; 1) ( for (int j - 1+ 1; j< 4; ++1) { if (words[1].compareTo(words[]]) > 0) { // swap words[1] with words[j[ String temp words[1]; words (1] - words [j]; words (j] - temp: System.out.print("In lexicographical order: "); for (int i 0; 1 < 4; i) ( System.out.printf( "%s ", words[1);

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Hello,,,. I hope you can help me with this code..

The questions to be answered are: (PLEASE REFER TO THE PHOTO FOR THE CODE)

1. WHAT IS THE OUTPUT OF THE PROGRAM?
2. HOW DOES THE PROGRAM WORK?

1. class Main (
2. public static void main(String[] args) {
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String[] words - { "Ruby", "C", "Python", "Java" };
for(int i 0; 1 < 3; ++1) {
for (int j - 1+ 1; j< 4; +) {
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if (words[1].compareTo(words[j]) > 0) {
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1/ swap words[1] with words[j[
String temp words[i];
words [1] - words []];
words [j] temp;
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System.out.print("In lexicographical order: ");
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for (int i - 0; 1 < 4; 1++) (
System.out.printf( "%s ", words[1]);
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25 }
Transcribed Image Text:1. class Main ( 2. public static void main(String[] args) { 3 4 String[] words - { "Ruby", "C", "Python", "Java" }; for(int i 0; 1 < 3; ++1) { for (int j - 1+ 1; j< 4; +) { 6- 7- 8 9. if (words[1].compareTo(words[j]) > 0) { 10 1/ swap words[1] with words[j[ String temp words[i]; words [1] - words []]; words [j] temp; 11- 12 13 14 15 16 17 18 19 System.out.print("In lexicographical order: "); 20 21- for (int i - 0; 1 < 4; 1++) ( System.out.printf( "%s ", words[1]); 22 23 24 25 }
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