MATLAB: An Introduction with Applications
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ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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Claim: The standard deviation of pulse rates of adult males is less than
12 bpm. For a random sample of 160 adult males, the pulse rates have a standard deviation of 10.7 bpm. Find the value of the test statistic.
The value of the test statistic is :
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- Use z scores to compare the given values. In a recent awards ceremony, the age of the winner for best actor was 33 and the age of the winner for best actress was 47. For all best actors, the mean age is 44.4 years and the standard deviation is 6.5 years. For all best actresses, the mean age is 32.8 years and the standard deviation is 11.2 years. (All ages are determined at the time of the awards ceremony.) Relative to their genders, who had the more extreme age when winning the award, the actor or the actress? Explain. Since the z score for the actor is z= and the z score for the actress is z = the V had the more extreme age. (Round to two decimal places.)arrow_forwardClaim: The mean pulse rate (in beats per minute) of adult males is equal to 69 bpm. For a random sample of 149 adult males, the mean pulse rate is 67.6 bpm and the standard deviation is 10.7 bpm. Find the value of the test statistic. The value of the test statistic is (Round to two decimal places as needed.)arrow_forwardClaim: The mean pulse rate (in beats per minute) of adult males is equal to 69 bpm. For a random sample of 156 adult males, the mean pulse rate is 70.2 bpm and the standard deviation is 11.1 bpm. Find the value of the test statistic. The value of the test statistic is (Round to two decimal places as needed.)arrow_forward
- Claim: The mean pulse rate (in beats per minute) of adult males is equal to 69 bpm. For a random sample of 137 adult males, the mean pulse rate is 70.2 bpm and the standard deviation is 10.7 bpm. Find the value of the test statistic. The value of the test statistic is (Round to two decimal places as needed.)arrow_forwardA distance is measured six times. The observed values are 572.182 m, 572.140 m, 572.103 m, 572.160 m, 572.125 m, and 572.155 m. All measurements are uncorrelated and their standard deviations are 0.030 m, 0.030 m, 0.030 m, 0.020 m, 0.020 m, and 0.010 m, respectively. Find the least squares estimate for the distance. Use matrices and R in the solution. Write the R commands involved.arrow_forwardClaim: The standard deviation of pulse rates of adult males is more than 11 bpm. For a random sample of 170 adult males, the pulse rates have a standard deviation of 12.2 bpm. Find the value of the test statistic. The value of the test statistic is (Round to two decimal places as needed.)arrow_forward
- Claim: The standard deviation of pulse rates of adult males is more than 12 bpm. For a random sample of 172 adult males, the pulse rates have a standard deviation of 11.5 bpm. Find the value of the test statistic?arrow_forwardUse z scores to compare the given values. In a recent awards ceremony, the age of the winner for best actor was 28 and the age of the winner for best actress was 44. For all best actors, the mean age is 42.3 years and the standard deviation is 8.4 years. For all best actresses, the mean age is 33.3 years and the standard deviation is 10.7 years. (All ages are determined at the time of the awards ceremony.) Relative to their genders, who had the more extreme age when winning the award, the actor or the actress? Explain. Since the z score for the actor is z = and the z score for the actress is z=, the had the more extreme age. (Round to two decimal places.)arrow_forwardClaim: The mean pulse rate (in beats per minute) of adult males is equal to 69 bpm. For a random sample of 172 adult males, the mean pulse rate is 70.1 bpm and the standard deviation is 11.4 bpm, Find the value of the test statistic. The value of the test statistic is.1 (Round to two decimal places as needed.)arrow_forward
- Claim: The standard deviation of pulse rates of adult males is less than 10 bpm. For a random sample of 173 adult males, the pulse rates have a standard deviation of 8.9 bpm. Find the value of the test statistic. The value of the test statistic is (Round to two decimal places as needed)arrow_forwardA farm hatches chicken eggs in batches of 15 and there is a 3% infertile rate. Find the standard deviation for the number of infertile eggs per batch. 0.2 O 0.44 0.45 O 0.66 O 43.7arrow_forwardUse Z-scores to determine which is a better relative golf score (remember that in golf, lower scores are better): Shooting a 75 in Tournament A where the mean score is 73 and the standard deviation is 3.3; or shooting a 76 in Tournament B where the mean score is 74 and the standard deviation is 3.5 .arrow_forward
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