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Claim: The mean pulse rate (in beats per minute) of adult males is equal to 69 bpm. For a random sample of 160 adult males, the mean pulse rate is 69.4 bpm and the standard deviation is 10.8 bpm. Find the value of the test statistic. The value of the test statistic is (Round to two decimal places as needed.)

Claim: The mean pulse rate (in beats per minute) of adult males is equal to 69 bpm. For a random sample of 160 adult males, the mean pulse rate is 69.4 bpm and the standard deviation is 10.8 bpm. Find the value of the test statistic. The value of the test statistic is (Round to two decimal places as needed.)

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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### Hypothesis Testing Example **Claim:** The mean pulse rate (in beats per minute) of adult males is equal to 69 bpm. For a random sample of 160 adult males, the mean pulse rate is 69.4 bpm and the standard deviation is 10.8 bpm. **Task:** Find the value of the test statistic. **Answer Box:** - [ ] *(Round to two decimal places as needed.)* ### Explanation To test this claim, we will use the formula for the test statistic for a sample mean: \[ z = \frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}}} \] Where: - \(\bar{x}\) is the sample mean (69.4 bpm) - \(\mu\) is the population mean as stated in the claim (69 bpm) - \(\sigma\) is the standard deviation of the sample (10.8 bpm) - \(n\) is the sample size (160) Use this formula to calculate the test statistic to assess the validity of the claim.
Transcribed Image Text:### Hypothesis Testing Example **Claim:** The mean pulse rate (in beats per minute) of adult males is equal to 69 bpm. For a random sample of 160 adult males, the mean pulse rate is 69.4 bpm and the standard deviation is 10.8 bpm. **Task:** Find the value of the test statistic. **Answer Box:** - [ ] *(Round to two decimal places as needed.)* ### Explanation To test this claim, we will use the formula for the test statistic for a sample mean: \[ z = \frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}}} \] Where: - \(\bar{x}\) is the sample mean (69.4 bpm) - \(\mu\) is the population mean as stated in the claim (69 bpm) - \(\sigma\) is the standard deviation of the sample (10.8 bpm) - \(n\) is the sample size (160) Use this formula to calculate the test statistic to assess the validity of the claim.
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