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Choose the correct product for the following reaction. xBr 1. NaN3 2. LIAIH4 (XS) 3. H₂O

Choose the correct product for the following reaction. xBr 1. NaN3 2. LIAIH4 (XS) 3. H₂O

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Reaction Product Selection** **Problem Statement:** Choose the correct product for the following reaction. **Reaction Sequence:** - **Starting Material:** Alkyl bromide compound - **Reagents and Conditions:** 1. Sodium azide (NaN₃) 2. Excess lithium aluminum hydride (LiAlH₄, xs) 3. Water (H₂O) **Product Options:** - **A:** Alkyl amine with the amine group on the terminal carbon - **B:** Alkyl amine with the amine group on the secondary carbon - **C:** Hydrocarbon with no functional groups - **D:** Alkyl azide with the azide group on the terminal carbon - **E:** Starting alkyl bromide compound **Choose One:** - A - B - C - D - E **Explanation:** The reaction in question involves an alkyl bromide undergoing substitution with sodium azide to form an alkyl azide. This intermediate then reacts with excess LiAlH₄, reducing the azide to an amine. Water is used in the final step to complete the reaction, resulting in an amine product. The correct product will reflect these transformations.
Transcribed Image Text:**Reaction Product Selection** **Problem Statement:** Choose the correct product for the following reaction. **Reaction Sequence:** - **Starting Material:** Alkyl bromide compound - **Reagents and Conditions:** 1. Sodium azide (NaN₃) 2. Excess lithium aluminum hydride (LiAlH₄, xs) 3. Water (H₂O) **Product Options:** - **A:** Alkyl amine with the amine group on the terminal carbon - **B:** Alkyl amine with the amine group on the secondary carbon - **C:** Hydrocarbon with no functional groups - **D:** Alkyl azide with the azide group on the terminal carbon - **E:** Starting alkyl bromide compound **Choose One:** - A - B - C - D - E **Explanation:** The reaction in question involves an alkyl bromide undergoing substitution with sodium azide to form an alkyl azide. This intermediate then reacts with excess LiAlH₄, reducing the azide to an amine. Water is used in the final step to complete the reaction, resulting in an amine product. The correct product will reflect these transformations.
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