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- 6| 17 aölJI - 2 uacl X 10 uluilg (-) X Content Google dai X 9 https://blackboard.uob.edu.bh/ultra/courses/ 24065 1/cl/outline Not syncing Remaining Time: 29 minutes, 53 seconds. * Question Completion Status: Consider a uniformly charged ring of radius R-0.2 m and linear charge density 2-3 µC/m as shown in the figure. Find the electric potential (in V) at (p) a distance 0.7 m from the center. 0 0.7 m 3.1x 10* 6.2 x 104 O9.3x 104 7.8x 104 O 4.7x10 7:05 PN 4/3/202 archarrow_forwardQuestion 1 A positively charged particle q= 12 µC is placed between two infinite charged sheets with surface charge density +a and-a as shown in the figure. If aj-3.54 µC/m², then the magnitude of the electric force (in N) on the particle is: 0.0 90 ON 48 0.00 0672arrow_forward8arrow_forward
- Questions 8-10 refer to the figure below. 91 а 92 а а 94 а 93 8. Four charges q1 = of the square have a length a. In terms of ke, Q, and a calculate the electric force acting on q1 due to q2, 93, and +Q, q2 = +Q, 93 = –Q, and q4 = -Q are in the corners of a square. The sides 4. A. ke (-0.65ây – 1.35g) C. kQ (0.65 + 1.35ŷ) В. К(-1.352 — 0.659) D. k (1.35â + 0.65ý) a2 a2 9. Four charges q1 = +Q, q2 = +Q, q3 = -Q, and q4 = -Q are in the corners of a square. The sides of the square have a length a. In terms of ke, Q, and a calculate the electric force acting on 2 due to q1, 93, and q4. A. k (0.65â – 1.35ŷ) C. E(-0.65£ + 1.35ŷ) D. g(-1,35 + 0.65ý) Q² B. k (1.35â – 0.65ý) 10. Four charges q1 = +Q, q2 = +Q, q3 = -Q, and q4 = -Q are in the corners of a square. The sides of the square have a length a. In terms of ke, Q, and a calculate the electric force acting on q3 due to q1, 92, and q4. A. k(-0.65â – 1.35g) B. k(-1.35â – 0.65ŷ) D. ke (1.35€ + 0.65ŷ) С. К (0.65 + 1.35)arrow_forward= Charges q₁ q2 = 93 = 10.0 μC have positions ₁ 73 = (0.00, 0.00). Calculate the electric force vector on charge q₁. Y 92 1.20 93 1.60 2.00m. qi 36.9° X 1.60 m î+ 1.20 mĵ72 = 1.20 m ĵ, andarrow_forwardGggarrow_forward
- Criterion A: Knowing and understanding i. state scientific knowledge. (Max. 2 points) Two small charged objects have charges of Q = -5.77 × 10-7 C and q = –1.23 × 10¬5 C. The force between them is 2.31 × 10-³ N. Calculate the distance between them (3SF). 1 Qq F 4TE0 p2 x10-3 N = 8.9875 × 10° N m² C-²×( x10-7 C× |x10-5 C) ÷r² 2.31 x 10-3 N = 8.9875 × 10° N m² C-2x( x10-12 C²) ÷r2 V((8.9875 × 10° N m? C-²× ×10-12 C²) ÷ x10-³ N) r = ||arrow_forwardUsing the values given below, find the electric field at point X due to the two charges q1 and 92. qi -0.077.μ., q,= 8.μ., a = 0.56_m, b = 0.2_m, c = 0.74_m %3D 5. magnitude 86230_N/C 90830_N/C 115400_N/C 238800_N/C 203900_N/C 123000_N/C A. D. В. Е. С. F. |--/ 0.7 lm r1 r2 C 6. direction А. 104.8° D. 141.2° a b 91 q2 % В. 167.6° E. 170.4° C. 152.1° F. 116° |--/arrow_forward
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