Two small charged objects have charges of Q = -5.77 × 10-7 C and q = -1.23 × 10-5 C. The force between them is 2.31 × 10¬³ N. %3D Calculate the distance between them (3SF). Qq F = 4πεο p2 x10-3 N 8.9875 x 10° N m² C-²×( ×10-7 Cx x10-5 C) ÷r² 2.31 x 10-3 N 8.9875 × 10° N m² C-²×( ]x10-12 C³) ÷r² = v((8.9875 × 10º N m² C-²×[ |x10-12 C²) ÷ |×10-³ N) r =

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Chapter1: Units, Trigonometry. And Vectors
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Criterion A: Knowing and understanding
i. state scientific knowledge. (Max. 2 points)
Two small charged objects have charges of Q = -5.77 × 10-7 C and q = –1.23 × 10¬5 C. The
force between them is 2.31 × 10-³ N.
Calculate the distance between them (3SF).
1
Qq
F
4TE0
p2
x10-3 N = 8.9875 × 10° N m² C-²×(
x10-7 C×
|x10-5 C) ÷r²
2.31 x 10-3 N = 8.9875 × 10° N m² C-2x(
x10-12 C²) ÷r2
V((8.9875 × 10° N m? C-²×
×10-12 C²) ÷
x10-³ N)
r =
||
Transcribed Image Text:Criterion A: Knowing and understanding i. state scientific knowledge. (Max. 2 points) Two small charged objects have charges of Q = -5.77 × 10-7 C and q = –1.23 × 10¬5 C. The force between them is 2.31 × 10-³ N. Calculate the distance between them (3SF). 1 Qq F 4TE0 p2 x10-3 N = 8.9875 × 10° N m² C-²×( x10-7 C× |x10-5 C) ÷r² 2.31 x 10-3 N = 8.9875 × 10° N m² C-2x( x10-12 C²) ÷r2 V((8.9875 × 10° N m? C-²× ×10-12 C²) ÷ x10-³ N) r = ||
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