Ꭰ CH3 t-BuO K +

Concentrated sulfuric acid is 18.0 M. What volume is needed to prepare 1.0 L of 6.0 M sulfuric acid solution? Report your answer with 2 SF

2. Given the following data: P4(s) + 6CI2(g) →> 4PCI3(g) AHrxn = 1225.6 kJ %3D P4(s) + 502(g) →> P4O10(s) AHrxn = -2967.3 kJ %3D PCI3(g) + Cl2(g)→ PCI5(g) AHrxn = -84.2 kJ %3D PCI3(g) + %02(g) → CI3PO(g) AHrxn = -285.7 kJ %3D Calculate AH for the reaction P4O10(s) + 6PCI5(g) → 10C13PO(g)

Use the set of three reactions shown below to answer the questions that follow.2NO(g) + O2(g) → 2NO2(g)     ΔH = -116 kJ2N2(g) + 5O2(g) + 2H2O(l) → 4HNO3(aq)     ΔH = -256 kJN2(g) + O2(g) → 2NO(g)     ΔH = +183 kJ If 35.5 g of NO g is reacted with excess oxygen, how much heat energy is produced?

Please answer these 2 for me

A 90.0 g piece of metal, initially at 98.6°C, is placed into 120.0 g of water initially at 24.3°C. If the final temperature of the water is 34.0°C, what is the specific heat of the metal? (The specific heat of water is 4.18 J/g. °C).

ORT SHEET Heat of Neutralization EXPERIMENT elemsboomfchg lom 12 A. Heat Capacity of Calorimeter 1. Temp. of calorimeter and water before mixing 2. Temp. of warm water °C 22.0 39,0 30.3 3. Maximum temp. determined from your curve °C 4. Heat lost by warm water (temp decrease x °C 50.0 g x 4.184 J/K-g) = 02), 5. Heat gained by cooler water (temp. increase x 50.0 g x 4.184 J/K-g) = 30,3 22.0)x 13626J s0.0gmpi S0.0gy 6. Heat gained by the calorimeter [(4) – (5)] = 7. Heat capacity of calorimeter: heat gained by the calorimeter temperature increase J/K 3. Heat of Neutralization of HCl-NaOH 22.2 22.2. °C . Temp. of calorimeter and NaOH Temp. of HCI AT determined from your curve after adding HC1 °C to the NaOH Heat gained by solution (temperature increase x ON 100 g x 4.184 J/K-g) = 9977.8J %3D Heat gained by calorimeter (temperature increase x heat capacity of calorimeter) = J %3D Total joules released by reaction [(3) + (4)] = Tight O 2018 Pearson Education, Inc.

HBr 50°C

Did I do this conversion correctly? (My answer is highlighted in red)

Which of the following collisions will initiate the reaction? The energy of the collision is written in kJ beside the possible orientation of the molecules. 130 kJ Reactants Activation Energy 100 kJ Products 15 kJ Reaction Progress Potential Energy [kJ]