Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- Four alleles determine a rabbit’s coat colour: agouti (C), chinchilla (cch), Himalayan (ch), and albino (c). The order of dominance is C > cch > ch > c. A chinchilla rabbit is crossed with an albino rabbit. What are the possible phenotypes of the offspring? Select one: a. Chinchilla and Himalayan b. Chinchilla, Himalayan, albino, and agouti c. Chinchilla, Himalayan, and albino d. Chinchillaarrow_forwardThree different genes determine the coat colour of cats. One of the genes controls the black-based coat colour. There are three alleles for black-based coat colour genes with the following order of dominance: black (B) > chocolate (bch) > cinnamon (bc). Two black cats were crossed. The offspring produced were three black kittens and one chocolate kitten. Which of the following rows identifies the possible genotype(s) of the parents? Select one: a. Parent 1 Parent 2 Bbch Bbch b. Parent 1 Parent 2 Bbch Bbc or Bbch c. Parent 1 Parent 2 Bbc Bbch d. Parent 1 Parent 2 B__ Bbcharrow_forwardPlease read the scenario below, and then answer the question (in bold) that follows. In cats, the allele (B) produces a black coat color and the allele (b) produces a yellow coat color. These alleles are incompletely dominant to each other. A heterozygote produces a tortoise shell coat color. The alleles (B) and (b) are also sex-linked (i.e., they are carried on the X chromosome), and cats possess an XX-XY sex determination system, like humans. If a female cat with a tortoise shell coat mated with a male cat who had a yellow coat... What gametes would be produced by the female (i.e., mother) cat? a. XBXb b. XB and Xb c. B and b d. Xb and Y e. None of the abovearrow_forward
- 1) In some species of pea plant, pea colour is determined by one pair of alleles and pea shape by another - the genes are on different chromosomes. A plant grown from a round green pea was self-pollinated. The following numbers of offspring were obtained: 95 green round, 28 white round, 30 green wrinkled, 11 white wrinkled. a) What is the ratio of the phenotypes in the offspring? b) In each pair of alleles, colour and shape, which allele is dominant and which recessive? c) what was the genotype of the parent(s)? Use a diagram to show how this explains the phenotype ratio of the offspring.arrow_forwardExample: Linkage - Drosophila Body Color / Eye Color Please choose two parent genotypes of dissimilar gender by dragging them into the parent cells at right. Then select check boxes to identify nonrecombinent and recombinent offspring. Click the clear button if you would like to start over. Xy+w+ xyw Xyw y (Xy+W+ хуш) (XyW+ xy+W) (Xyw y) Nonrecombinent phenotypes: Nonrecombinent genotype: Recombinent genotype: Female/males with gray body/red eyes; females/males with yellow body/white eyes. Female/male with gray body/white eyes; female/male with yellow body/red eyes. Female/male with gray body/white eyes; female/male with yellow body/red eyes. Female/male with gray body/red eyes; female/male with yellow body/white eyes. Clear Recombinent phenotypes: Help Xy+w+ xyw Xy+w xyw XyW+ xyw Xyw xyw Xy+w+y Xy+wy XyW+ y Xyw y Submitarrow_forwardSuppose a geneticist is using a three-point test cross to map three linked rabbit morphology and behavioral mutations called si, sf, and H. The gene si is associated with the silky fur phenotype, and sf is associated with the short-footed phenotype. Both si and sf are recessive mutations with respect to wild type. H is a dominant mutation that confers the hyper phenotype. The geneticist first crosses true-breeding hyper rabbits to true-breeding silky fur, short-footed rabbits. Next, the geneticist backcrosses the F₁ progeny to the silky fur, short-footed parents, and obtains the results reported in the table. Phenotype hyper silky fur, short-footed short-footed silky fur, hyper silky fur short-footed, hyper silky fur, short-footed, hyper wild type Place the genes in the correct order in the chromosome. LLIIN HEL H Number 815 807 175 169 4 5 27 29 Answer Bank si sfarrow_forward
- In cats, the locus for orange coat color is sex linked. Male cats that are black have the o+ allele, whereas those that are orange have the o allele. Females can be homozygous for the orange allele or homozygous for the black allele and will express each color, respectively. Heterozygous females are tortoise-shelled or calico, having orange and black patches. A calico cat, in addition to being heterozygous at the orange locus, also is either heterozygous or homozygous for the incompletely dominant, autosomal spotting allele (SS = large spots, Ss = small spots, ss = no spots). Manx tails are caused by a dominant trait that is lethal when homozygous. Long tails are the result of a homozygous recessive genotype. An orange male with small white spots and a manx tail is crossed to a calico female with small white spots and a manx tail. What is the probability of observing a solid black female with no spots and long tail? (Hint: All calico cats are female!)arrow_forwardMost sheep have the ability to grow coats of wool that vary in their thickness depending on the ambient temperatures that they experience. This is an aspect of phenotypic plasticity, variability in the phenotype that can be triggered by the experiences of the organism. When referring to a sheep that has grown more wool in a cold climate than its parents living in a warm one, what term best describes this? (NOTE: look back at chapter 25, if you are having trouble remembering) O Adaptation Intersexual selection Intrasexual selection Acclimitization Gene Fixationarrow_forwardAssume that a single gene determines coat coloration in cats, with the B allele resulting in orange coloration, and b allele results in black coloration. This gene exists on the X chromosome (recall that cats have XX/XY system of sex determination). My cat Pepper is a female tortoiseshell, and my cat Hobbes is an orange male. (i) What is the probability that Hobbes and Pepper have three kittens, Hopper (male), Pepsi (female), and Hippie (female)? What is the probability that they have three kittens, and that Hopper (male), and Hippie (female) are both orange, and that Pepsi (female) is a tortoiseshell? (ii) Distribution of % of Barr Bodies in each body part 120 100 100 80 100 60 40 50 50 20 Head Body Tail Black Orangearrow_forward
- You cross true breeding blue and red morning glories and get all blue offspring. a) Based on this information alone: i) How many loci are involved in the expression of this trait? How many alleles? What are the dominant and recessive interactions between the alleles at the locus/loci? ii)what are the possible genotypes of the parents and F1s? iii) Based on your hypothesized genotypes from ii, what do you expect the outcome of a cross between the F1's to be? (i.e. what phenotypes in what ratios?) b) You then cross the F1 individuals and you obtain the following results Blue - 200 purple - 126 red - 24 i) Are these results statistically consistent with your hypothesis above? (prove it!) ii) If not, what is an alternative hypothesis that might explain these results? Are these results the result of one locus or 2? Test your new hypothesis using chi-squared test. Discuss the meaning of your results. (Note: If your hypothesis proves wrong, that is OK!!! But you have to be able to discuss…arrow_forwardAn allelic series determines coat color in rabbits: C (full color), cch (chinchilla, gray color), c* (Himalayan, white with black extremities), and c (albino, all white). The C allele is dominant over all others, cch is dominant over c and c, ch is dominant over c, and c is recessive to all other alleles. This dominance hierarchy can be summarized as C> cch > c^ > c. The rabbits in the table are crossed and produce the progeny shown. Cross Parents Offspring А full color x albino 50% full color, 50% albino В Himalayan x albino 50% Himalayan, 50% albino C full color x albino 50% full color, 50% chinchilla D full color × Himalayan 50% full color, 25% Himalayan, 25% albino E full color x full color 75% full color, 25% albino Match the parental genotypes to the letter corresponding to the appropriate cross listed in the table. A В C D E Answer Bank Ccch x cc Cc x cc СС х сс hch x cc Сс х сс Сс х Сс chc x ccarrow_forwardReferring to the pattern of inheritance of comb type and feathering in chicken, consider the cross between the following: a hen heterozygous for hen feathering and walnut comb and a cock feathered roster with single comb. What are the genotypes and phenotypes of their male and female offspring?arrow_forward
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