Carefully study the following plot of electric field E in  N/C versus distance r in  m and answer the questions that follow. The electric field is directed radially outward, and the variation of E with r is independent of direction. Referring to the figure above, determine the work done by the electric field on a 2.6μ C charge moved from A to B.

Please solve subparts A,B,C max 30 minutes pleaase and send here. Thank u   Two charges of +Q each are placed x = a and x = - a A. Determine the electric field at the point (0,y) B. A small object with mass m and charge q can move freely along the y axis. Determine the force experienced by the object if the object is initially at (0,y) C. Determine the type of object in such a way that the force experienced by the object always has direction to the origin (0,0)

ℓ = 9 cm, and Q = 3 μ C. Calculate the potential energy of the right-side charge, in Joules. Please be careful of units.  If you blow off units, you will get a wrong answer, and the system will count it wrong.   Diagram is attached.

You Answered Correct Answer A line of charge is placed along the negative x axis from x=-0.4m to x=0. The charge is uniformly distributed with linear charge density 3.06pC/m. A proton is released from rest at a point on the positive x axis 2.53m. When the proton has a speed of 472.1m/s, how far will it have moved (in m}? 1.0975 margin of error +/-1%

Electrostatic forces are conservative. This means that mechanical energy (KE +PE) is constant or conserved in absence of other dissipative forces such as friction. If a charged particle moves from point A to point B in an electric field (assume that dissipative forces such as friction are absent), select all the statements that are true. The symbol A represents the change in the particular quantity. Recall what does positive and negative work mean? Reflect on what the negative sign represents in each case? Select multiple answers. APE=-Work A→B i.e., for positive work, PE decreases and for negative work, PE increases ΔΚΕ # -ΔΡΕ ✓ changes in KE and PE are not connected. ΔΚΕ = -ΔΡΕ i.e., if KE increases, PE decreases and vice-versa APE=WorkAB Ⓒi.e., for positive work, PE increases and for negative work, PE decreases

b and c please

Question 6 and 7. Index to show all work said assume that R = 2.43 m and c = 1.47 nC/m^4 the total charge of the disk

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