Carbon monoxide is a colorless, odorless gas that binds irreversibly to hemoglobin in our blood, causing suffocation and death. CO is formed during incomplete combustion of carbon. One way to represent this equilibrium is: ? C(s) + 1/2O₂(g) CO(g) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above. 1) 2 C(s) + O₂(g) 2 2C0(g) K₁ = K² 2) 200(g) 22 C(s) + O₂(g) K₂ = 1/K 3) CO(g) 2 C(s) + 1/2O₂(g) K3 = (1/K)² Drag and drop your selection from the following list to complete the answer: K² 1/K (1/K)²

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Chapter1: Chemical Foundations
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Carbon monoxide is a colorless, odorless gas that binds
irreversibly to hemoglobin in our blood, causing
suffocation and death.
CO is formed during incomplete combustion of carbon.
One way to represent this equilibrium is:
?
C(s) + 1/2O₂(g) CO(g)
We could also write this reaction three other ways, listed below. The equilibrium constants for all
of the reactions are related. Write the equilibrium constant for each new reaction in terms of K,
the equilibrium constant for the reaction above.
1) 2 C(s) + O₂(g) 2 2c0(g)
K₁
2)2CO(g)
22 C(s) + O₂(g)
K₂ =
3) CO(g)
2 C(s) + 1/2O₂(g)
K3 =
Drag and drop your selection from the following list to complete the answer:
K²
1/K
(1/K)²
=
K²
1/K
(1/K) ²
Transcribed Image Text:Carbon monoxide is a colorless, odorless gas that binds irreversibly to hemoglobin in our blood, causing suffocation and death. CO is formed during incomplete combustion of carbon. One way to represent this equilibrium is: ? C(s) + 1/2O₂(g) CO(g) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above. 1) 2 C(s) + O₂(g) 2 2c0(g) K₁ 2)2CO(g) 22 C(s) + O₂(g) K₂ = 3) CO(g) 2 C(s) + 1/2O₂(g) K3 = Drag and drop your selection from the following list to complete the answer: K² 1/K (1/K)² = K² 1/K (1/K) ²
Methanol liquid burns readily in air.
One way to represent this equilibrium is:
CH₂OH(1) + 3/2 0₂(g) CO₂(g) + 2 H₂O(g)
We could also write this reaction three other ways, listed below. The equilibrium constants for all
of the reactions are related. Write the equilibrium constant for each new reaction in terms of K,
the equilibrium constant for the reaction above.
1) 2 CH₂OH(1) + 3 O₂(g)
2) 2 CO₂(g) + 4H₂O(g)
2 CO₂(g) + 4H₂O(g)
2 CH₂OH(1) + 3 O₂(g)
CH₂OH(1) + 3/2 0₂(g) K3
K₁ =
K₂ =
3) CO₂(g) + 2 H₂O(g)
Drag and drop your selection from the following list to complete the answer:
K²
(1/K)²
1/K
Transcribed Image Text:Methanol liquid burns readily in air. One way to represent this equilibrium is: CH₂OH(1) + 3/2 0₂(g) CO₂(g) + 2 H₂O(g) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above. 1) 2 CH₂OH(1) + 3 O₂(g) 2) 2 CO₂(g) + 4H₂O(g) 2 CO₂(g) + 4H₂O(g) 2 CH₂OH(1) + 3 O₂(g) CH₂OH(1) + 3/2 0₂(g) K3 K₁ = K₂ = 3) CO₂(g) + 2 H₂O(g) Drag and drop your selection from the following list to complete the answer: K² (1/K)² 1/K
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