Cantilever beam is rectrangular in section having (80 mm width) and (120 mm depth). If the cantilever is subjected to a point load of (6 kN) at the free end and the bending stress is not to exceed (40 MPa), find the span of the cantilever *.beam 6 kN 120 mm 80 mm
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- A steel beam having a span of 14 m. carries a dead load concentrated load Pp = 60 kN at its midspan. The beam is laterally supported at its span. Properties of the wide flange section. rts - 104.39 mm ho - 338.08 mm Jo -1.69 x 10^6 Cw - 4.3 x 10^12 d=356.11 mm tf = 18.03 mm tw - 11.18 mm Sx - 2343 x 103 mm rx = 155.96 mm ry - 93.98 mm Sy = 818 x 10^3 mm Zx = 2573 x 10^3 mm Zy= 1239 x 10^3 mm Fy = 345 MPa Iy = 151 x 10 mm Lp=3.98 Lb=14m Lr=12.98 Cb=1.14 Determine the safe concentrated live load that the beam could support at the center based on its design strengthDetermine the force of the members for the space truss shown in the figure. Joints A and B are supported by ball-and-socket while Joint C is supported by short link along z-axis. Indicate whether member is tension (T) or compression (C). 2m y Sm Az By BX Bz PAR Ax CSXScanned with Ca canner a SISU KN 15m 1 2117Where is/are the location(s) of the maximum transverese shear stress? A simple I-beam is loaded as shown. 20 mm P KN PKN PKN Į Į -C B с D L/4 m L/4 m Midspan at point C Roller at E at the NA Section B at the top fiber Pin A at point C Midspan at point D Roller E at point D L/4 m L/4 m OE 20 mm 20 mm- 250 mm 150 mm 150 mm A
- Problem 2 Given is a truss structure: Where: • Working shear stress for the rivets is 70 MPa • Working bearing stress due to rivets is 140 Mpa • Thickness of the member is 5 mm • Thickness of the Gusset plate is 6 mm Rivet diameter is 15 mm Determine the no. of rivets to fasten the member BD 80 N 120 N 200 N 4 Pands 4m - 16 m0O REDMI NOTE 8 PRO O AI QUAD CAMERA Q - 4. For the given truss structure below; BY USING THE METHOD of SECTIONS; determine the internal forces of the elements BD, CD & CE. Also determine whether these forces are TENSILE or COMPRESSIVE. 3 in 3 m -4 m -4 m -4 m- 1.75 kN 2KN 1.5 kN 2kN I kN 9.75 kN G 6 m 6 m 6m 6 mThe beam cross-section shown is design to resist a nominal moment M₁ of 320 kN m, if f = 35 MPa and fy = 420 MPa, determine the required area of steel reinforcement Ag. 75,75,75 As 225- 75 565 60 700mm 0.85f I N2 0.85f d 1-17/22 T₁ T = T₁+T₂ d C₂ a-75 I a-75 2 T₂
- Q2) The members of the truss structure shown below is plain concrete. The compressive strength of the concrete is 25 MPa. Compute the maximum load P that can be carried by the structure. (Cross section of each member of the truss is 200 x 200 mm and don't use material factors and do not consider slenderness) Comment on your results briefly. P A& 2m SC 2 m 1380 2m DA wide flange section has the following properties. A- 6645 mm2 by - 152.40 mm t- 10.80 mm d- 449.58 mm tw - 7.62 mm F,- 250 MPa Compute the plastic section about the minor principal axis. (x 10° mm)A bracket of length 1.5m is rigidly attached to the simply-supported beam at its end. The beam is subjected to the combined effect of M,, M, and compressive force P caused by the factored loads as shown. There are lateral supports only at the ends. The member is made of HE300A section and steel grade is S275 (Fy-275MPA, Fu= 430 MPa). The loads acting are determined from LRFD combinations. Determine whether the member can safely carry the applied loads. Multiply first-order moment diagrams by a factor of 1.2 to account for second-order effects. No need to check shear limit state. You do not need to additionally consider the beam self-weight. E Use the following simple expression to calculate the value of L:: L, = T*rts 0.7*Fy y P = 400kN 1.5 m F = 150kN 2 т 4 т X: Lateral support НЕЗ00А
- The built-up section shown below is fastened together by passing two 10 mm diameter rivets through the top and bottom plates into the flanges of the beam. Each rivet will withstand 11.8 kN in shear. Determine the required spacing of the rivets along the length of the beam if it carries a shearing force of 199 kN. 12 mm x 180 mm plates (2) I IPE I 400x180x642.2 steel 10 mm rivetsAcantilever beam AB, loaded by a uniform load (see figure), is applied on a channel section. If the cross section has the dimensions indicated and the moment of inertia about the z axis (the neutral axis) is I= 3.36 in" Find the maximum tensile stress fhtMAX and maximum compressive stress facMAX (Note: Draw the shear and moment diagram). 2.5 lb/ft 0.617 in. Z- C 2.269 in. 6.0 ftW3D 25 Y= 155 %31 1oow= 2500 KN 27=310mm X= 475 Z= 60 %3D 102=600mm