Calculate: a) the vertical support reaction in support A. When sketching FBD, set the positive directions of both reactions in the positive direction of y axis. Enter your answer in kN to three decimal places

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter6: Stresses In Beams (advanced Topics)
Section: Chapter Questions
Problem 6.8.1P: A simple beam with a W 10 x 30 wide-flange cross section supports a uniform load of intensity q =...
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A steel beam, of lengths a = 5 m and b = 2 m and a hollow box cross section, is supported by a hinge support A and roller support B, see Figure Q.1. The width and height of the cross section are 200 mm and 300 mm, respectively, and the wall thickness of the cross section is 5 mm. The beam is under a distributed load of the intensity that linearly varies from q = 0 kN/m to q = 5.1 kN/m for AB span; and is constant with q = 5.1 kN/m for BC span. The Young’s modulus of steel is 200 GPa.

 

Calculate:

a) the vertical support reaction in support A. When sketching FBD, set the positive directions of both reactions in the positive direction of y axis. Enter your answer in kN to three decimal places.

A steel beam, of lengths a = 5 m and b = 2 m and a hollow box cross section, is supported by a hinge support A and roller support B, see Figure Q.1. The width
and height of the cross section are 200 mm and 300 mm, respectively, and the wall thickness of the cross section is 5 mm. The beam is under a distributed
load of the intensity that linearly varies from q = 0 kN/m to q = 5.1 kN/m for AB span; and is constant with q= 5.1 kN/m for BC span. The Young's modulus of
steel is 200 GPa.
Part A
Calculate:
▲y, v
A
a
9
mim
Дв
5 mm
200 mm
Figure Q.1
300 mm
b
C
X
a) the vertical support reaction in support A. When sketching FBD, set the positive directions of both reactions in the positive direction of y axis. Enter your
answer in kN to three decimal places.
Transcribed Image Text:A steel beam, of lengths a = 5 m and b = 2 m and a hollow box cross section, is supported by a hinge support A and roller support B, see Figure Q.1. The width and height of the cross section are 200 mm and 300 mm, respectively, and the wall thickness of the cross section is 5 mm. The beam is under a distributed load of the intensity that linearly varies from q = 0 kN/m to q = 5.1 kN/m for AB span; and is constant with q= 5.1 kN/m for BC span. The Young's modulus of steel is 200 GPa. Part A Calculate: ▲y, v A a 9 mim Дв 5 mm 200 mm Figure Q.1 300 mm b C X a) the vertical support reaction in support A. When sketching FBD, set the positive directions of both reactions in the positive direction of y axis. Enter your answer in kN to three decimal places.
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Follow-up Question

can you help me with this question please ;

the value of the maximum bending moment in the beam. Enter your answer in kNm to three decimal places.

Note: when deriving internal moment equations, use the following orientation of x coordinate:

 

  • Segment ABx changes from 0 at support A to a at support B. After making the cut, keep the part of the beam left from the cut.
  • Segment BC:  x changes from a at support B to L at point C, where L = a + b. After making the cut, keep the part of the beam right from the cut, i.e. distance from point C to the cut is equal L-x.
c) the value of the maximum bending moment in the beam. Enter your answer in kNm to three decimal places.
Note: when deriving internal moment equations, use the following orientation of x coordinate:
Segment AB: x changes from 0 at support A to a at support B. After making the cut, keep the part of the beam left from the cut.
Segment BC: xchanges from a at support B to L at point C, where L = a + b. After making the cut, keep the part of the beam right from the cut, i.e. distance
from point C to the cut is equal L-x.
●
Transcribed Image Text:c) the value of the maximum bending moment in the beam. Enter your answer in kNm to three decimal places. Note: when deriving internal moment equations, use the following orientation of x coordinate: Segment AB: x changes from 0 at support A to a at support B. After making the cut, keep the part of the beam left from the cut. Segment BC: xchanges from a at support B to L at point C, where L = a + b. After making the cut, keep the part of the beam right from the cut, i.e. distance from point C to the cut is equal L-x. ●
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Follow-up Question

Can you now find the vertical support reaction in support B

Enter your answer in kN to two decimal places.

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