**Electric Circuit Analysis Problem** The voltage \( V \) (volts), current \( I \) (amperes), and resistance \( R \) (ohms) of an electric circuit are related by the equation \( V = IR \). Suppose that \( V \) is increasing at the rate of 2 volts/second while \( I \) is decreasing at the rate of \( \frac{1}{4} \) ampere/second. Let \( t \) denote time in seconds. ### Questions: **A. What is the value of \( \frac{dV}{dt} \)?** **B. What is the value of \( \frac{dI}{dt} \)?** **C. Write the equation that relates \( \frac{dV}{dt} \), \( \frac{dI}{dt} \), and \( \frac{dR}{dt} \).** **D. Find the rate of change in \( R \) if \( V = 20 \) volts and \( I = 5 \) amps. Is \( R \) increasing or decreasing?** ### Solution Guide: To answer these questions, follow these steps: **For parts A and B:** - The rate of change of voltage \( \frac{dV}{dt} \) is given as 2 volts/second. - The rate of change of current \( \frac{dI}{dt} \) is given as \( -\frac{1}{4} \) amperes/second (since \( I \) is decreasing). **For part C:** 1. Differentiate the equation \( V = IR \) with respect to time \( t \): \[ \frac{d}{dt}(V) = \frac{d}{dt}(I \cdot R) \] 2. Apply the product rule of differentiation: \[ \frac{dV}{dt} = I \frac{dR}{dt} + R \frac{dI}{dt} \] **For part D:** 1. Substitute the known values into the differentiated equation: \[ 2 = 5 \frac{dR}{dt} + R \left( -\frac{1}{4} \right) \] 2. Solve for \( \frac{dR}{dt} \). **Calculation Steps:** 1.

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**Electric Circuit Analysis Problem**

The voltage \( V \) (volts), current \( I \) (amperes), and resistance \( R \) (ohms) of an electric circuit are related by the equation \( V = IR \). Suppose that \( V \) is increasing at the rate of 2 volts/second while \( I \) is decreasing at the rate of \( \frac{1}{4} \) ampere/second. Let \( t \) denote time in seconds.

### Questions:

**A. What is the value of \( \frac{dV}{dt} \)?**

**B. What is the value of \( \frac{dI}{dt} \)?**

**C. Write the equation that relates \( \frac{dV}{dt} \), \( \frac{dI}{dt} \), and \( \frac{dR}{dt} \).**

**D. Find the rate of change in \( R \) if \( V = 20 \) volts and \( I = 5 \) amps. Is \( R \) increasing or decreasing?**

### Solution Guide:

To answer these questions, follow these steps:

**For parts A and B:**
- The rate of change of voltage \( \frac{dV}{dt} \) is given as 2 volts/second.
- The rate of change of current \( \frac{dI}{dt} \) is given as \( -\frac{1}{4} \) amperes/second (since \( I \) is decreasing).

**For part C:**
1. Differentiate the equation \( V = IR \) with respect to time \( t \):
   \[
   \frac{d}{dt}(V) = \frac{d}{dt}(I \cdot R)
   \]
2. Apply the product rule of differentiation:
   \[
   \frac{dV}{dt} = I \frac{dR}{dt} + R \frac{dI}{dt}
   \]

**For part D:**
1. Substitute the known values into the differentiated equation:
   \[
   2 = 5 \frac{dR}{dt} + R \left( -\frac{1}{4} \right)
   \]
2. Solve for \( \frac{dR}{dt} \).

**Calculation Steps:**
1.
Transcribed Image Text:**Electric Circuit Analysis Problem** The voltage \( V \) (volts), current \( I \) (amperes), and resistance \( R \) (ohms) of an electric circuit are related by the equation \( V = IR \). Suppose that \( V \) is increasing at the rate of 2 volts/second while \( I \) is decreasing at the rate of \( \frac{1}{4} \) ampere/second. Let \( t \) denote time in seconds. ### Questions: **A. What is the value of \( \frac{dV}{dt} \)?** **B. What is the value of \( \frac{dI}{dt} \)?** **C. Write the equation that relates \( \frac{dV}{dt} \), \( \frac{dI}{dt} \), and \( \frac{dR}{dt} \).** **D. Find the rate of change in \( R \) if \( V = 20 \) volts and \( I = 5 \) amps. Is \( R \) increasing or decreasing?** ### Solution Guide: To answer these questions, follow these steps: **For parts A and B:** - The rate of change of voltage \( \frac{dV}{dt} \) is given as 2 volts/second. - The rate of change of current \( \frac{dI}{dt} \) is given as \( -\frac{1}{4} \) amperes/second (since \( I \) is decreasing). **For part C:** 1. Differentiate the equation \( V = IR \) with respect to time \( t \): \[ \frac{d}{dt}(V) = \frac{d}{dt}(I \cdot R) \] 2. Apply the product rule of differentiation: \[ \frac{dV}{dt} = I \frac{dR}{dt} + R \frac{dI}{dt} \] **For part D:** 1. Substitute the known values into the differentiated equation: \[ 2 = 5 \frac{dR}{dt} + R \left( -\frac{1}{4} \right) \] 2. Solve for \( \frac{dR}{dt} \). **Calculation Steps:** 1.
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