Calculate the work done by the force F→ when the car moves from x = 0 to x = 7.0 m. Calculate the work done by the force F→ when the car moves from x = 7.0 m to x = 2.0 m.

A man starts at ground level and carries a 20 kg box up a flight of stairs to a height of 3.6 m. He then carries the box down an adjacent flight of stairs back to ground level and ends up 10 m away from where he started. What is the total amount of work the man has done? Explain

An object is subject to a nonconstant force  F = (5x3 − 4x)  such that the force is in newtons when x is in meters. Determine the work done on the object as a result of this force as the object moves from  x = 0  to  x = 1.30 ✕ 102 m.

Ex(N) 80 50 25 X(m) 10 25 40 50 58 1) Work by a force, drawn on a graph, determine: a) The total work done by the force. b) Work at (10sx<40) m?

A child of mass m = 27 kg slides down a slide of height h = 2.1 m without friction. Let gravitational potential energy be zero at ground level. Write an expression for the child's total mechanical energy, E, at the top of the slide, in terms of the variables in the problem and the acceleration due to gravity g.  Calculate the change in the child's potential energy, ΔU in joules, from the top to the bottom of the slide at ground level (i.e. ΔU = Uground- Utop).  What is the child's final speed, vf in m/s?

On a horizontal surface, an object slides from point P to point Q along a straight line, then slides back from Q to P along a semicircle. If P and Q are a distance L apart, how much work did the force of kinetic friction do during the entire process? The magnitude of fk is fk.

State the condition when the work done by a force is (a) positive (b) negative. Explain with help of examples.

During terrible weather at a ski-flying world championship, a ski jumper tried to adjust for bad conditions midway down the ramp but completely lost control and tumbled wildly off the side at its bottom into a scattering crowd. The 73-kg jumper left the ramp about 45 m lower than his starting position. After hitting the ground, the jumper crashed wildly and descended down the hill another 20 vertical meters before coming to rest. Here, friction cannot be ignored. Calculate the total work done on the ski jumper to bring him to rest. Round the final answer to the nearest whole number.

A force = (8x + 7y ) N acts on an object as if moves in the x direction from the origin to x = 7.00 m. Find the work done on the object by the force.

A block of mass m = 2.50 kg is pushed d = 2.80 m along a frictionless horizontal table by a constant applied force of magnitude F = 15.0 N directed at an angle 8 = 25.0° below the horizontal as shown in the figure below. m (a) Determine the work done by the applied force. (b) Determine the work done by the normal force exerted by the table. (c) Determine the work done by the force of gravity. J (d) Determine the work done by the net force on the block.