A roller-coaster car of mass 1.50 × 103 kg is initially at the top of a rise at point Ⓐ. It then moves 35.0 m at an angle of 50.0° below the horizontal to a lower point Ⓑ. (a) Find both the potential energy of the system when the car is at points Ⓐ and Ⓑ and the change in potential energy as the car moves from point Ⓐ to point Ⓑ, assuming y = 0 at point Ⓑ. (b) Repeat part (a), this time choosing y = 0 at point Ⓒ, which is another 15.0 m down the same slope from point Ⓑ.

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Chapter1: Units, Trigonometry. And Vectors
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A roller-coaster car of mass 1.50 × 103 kg is initially at the top of a rise at point Ⓐ. It then moves 35.0 m at an angle of 50.0° below the horizontal to a lower point Ⓑ. (a) Find both the potential energy of the system when the car is at points Ⓐ and Ⓑ and the change in potential energy as the car moves from point Ⓐ to point Ⓑ, assuming y = 0 at point Ⓑ. (b) Repeat part (a), this time choosing y = 0 at point Ⓒ, which is another 15.0 m down the same slope from point Ⓑ.

Expert Solution
Step 1

Given,

Physics homework question answer, step 1, image 1

Step 2

Initial height of A is found using, 

Physics homework question answer, step 2, image 1

(a) Potential energy is given by,Physics homework question answer, step 2, image 2

For B, h = 0.

Hence, U = 0

For A, 

Physics homework question answer, step 2, image 3

Change in potential energy, 

Physics homework question answer, step 2, image 4

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