A roller-coaster car of mass 1.50 × 103 kg is initially at the top of a rise at point Ⓐ. It then moves 35.0 m at an angle of 50.0° below the horizontal to a lower point Ⓑ. (a) Find both the potential energy of the system when the car is at points Ⓐ and Ⓑ and the change in potential energy as the car moves from point Ⓐ to point Ⓑ, assuming y = 0 at point Ⓑ. (b) Repeat part (a), this time choosing y = 0 at point Ⓒ, which is another 15.0 m down the same slope from point Ⓑ.
A roller-coaster car of mass 1.50 × 103 kg is initially at the top of a rise at point Ⓐ. It then moves 35.0 m at an angle of 50.0° below the horizontal to a lower point Ⓑ. (a) Find both the potential energy of the system when the car is at points Ⓐ and Ⓑ and the change in potential energy as the car moves from point Ⓐ to point Ⓑ, assuming y = 0 at point Ⓑ. (b) Repeat part (a), this time choosing y = 0 at point Ⓒ, which is another 15.0 m down the same slope from point Ⓑ.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A roller-coaster car of mass 1.50 × 103 kg is initially at the top of a rise at point Ⓐ. It then moves 35.0 m at an angle of 50.0° below the horizontal to a lower point Ⓑ. (a) Find both the potential energy of the system when the car is at points Ⓐ and Ⓑ and the change in potential energy as the car moves from point Ⓐ to point Ⓑ, assuming y = 0 at point Ⓑ. (b) Repeat part (a), this time choosing y = 0 at point Ⓒ, which is another 15.0 m down the same slope from point Ⓑ.
Expert Solution
Step 1
Given,
Step 2
Initial height of A is found using,
(a) Potential energy is given by,
For B, h = 0.
Hence, U = 0
For A,
Change in potential energy,
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