MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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Maxima and Minima
The extreme points of a function are the maximum and the minimum points of the function. A maximum is attained when the function takes the maximum value and a minimum is attained when the function takes the minimum value.
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A derivative means a change. Geometrically it can be represented as a line with some steepness. Imagine climbing a mountain which is very steep and 500 meters high. Is it easier to climb? Definitely not! Suppose walking on the road for 500 meters. Which …
Concavity
In calculus, concavity is a descriptor of mathematics that tells about the shape of the graph. It is the parameter that helps to estimate the maximum and minimum value of any of the functions and the concave nature using the graphical method. We use the …
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# Calculate the Standard Error and Assess Normality ## Instructions - **Calculate the standard error**: You will calculate the standard error for each set of values given. - **Assess normality**: Determine if normality may be assumed. - **Round your answers to 4 decimal places**. ## Data Table ### Parameters: - **n**: sample size - **π**: population proportion | ( ) | | Standard Error | Normality | |-----|---|----------------|-----------| | **(a)** | \( n = 30, \; \pi = .60 \) | | Yes | | **(b)** | \( n = 58, \; \pi = .57 \) | | Yes | | **(c)** | \( n = 110, \; \pi = .59 \) | | Yes | | **(d)** | \( n = 550, \; \pi = .006 \) | | No | ## Explanation - **Standard Error**: To be calculated and filled in. - **Normality**: Indicates whether the assumption of normality can be made based on the sample size and proportion given. ### Notes: 1. Use the formula for the standard error of the proportion: \[ SE = \sqrt{\frac{\pi(1 - \pi)}{n}} \] 2. For normality, generally, if both \( n\pi \) and \( n(1-\pi) \) are greater than 5, normality can be assumed. **Students are required to fill in the Standard Error column with the calculated values.**
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Transcribed Image Text:# Calculate the Standard Error and Assess Normality ## Instructions - **Calculate the standard error**: You will calculate the standard error for each set of values given. - **Assess normality**: Determine if normality may be assumed. - **Round your answers to 4 decimal places**. ## Data Table ### Parameters: - **n**: sample size - **π**: population proportion | ( ) | | Standard Error | Normality | |-----|---|----------------|-----------| | **(a)** | \( n = 30, \; \pi = .60 \) | | Yes | | **(b)** | \( n = 58, \; \pi = .57 \) | | Yes | | **(c)** | \( n = 110, \; \pi = .59 \) | | Yes | | **(d)** | \( n = 550, \; \pi = .006 \) | | No | ## Explanation - **Standard Error**: To be calculated and filled in. - **Normality**: Indicates whether the assumption of normality can be made based on the sample size and proportion given. ### Notes: 1. Use the formula for the standard error of the proportion: \[ SE = \sqrt{\frac{\pi(1 - \pi)}{n}} \] 2. For normality, generally, if both \( n\pi \) and \( n(1-\pi) \) are greater than 5, normality can be assumed. **Students are required to fill in the Standard Error column with the calculated values.**
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