Calculate the standard enthalpy of formation of N2O5 at 298 K from the following data (all at 298 K):   2NO(g) + O2(g) ---> 2No2(g), delta H = -114.1 kJ/mol 4NO2(g) + O2(g) ---> 2N2O5(g), delta H = -110.2 kJ/mol N2(g) + O2(g) --> 2NO(g), delta H = +180.5 kJ/mol

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Calculate the standard enthalpy of formation of N2O5 at 298 K from the following data (all at 298 K):

 

2NO(g) + O2(g) ---> 2No2(g), delta H = -114.1 kJ/mol

4NO2(g) + O2(g) ---> 2N2O5(g), delta H = -110.2 kJ/mol

N2(g) + O2(g) --> 2NO(g), delta H = +180.5 kJ/mol

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