Calculate the molality of a 0.533 M aqueous solution of iron(II) chloride with a density, p = 1.059 g/mL. Report answer in three significant figures.

General, Organic, and Biological Chemistry
7th Edition
ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:H. Stephen Stoker
Chapter8: Solutions
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Problem 8.9EP: A solution is made by dissolving 34.0 g of NaCl in 100 g of H2O at 0C. Based on the data in Table...
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Calculate the molality of a 0.533 M aqueous solution of iron(II) chloride with a density, p = 1.059 g/mL. Report answer in three significant figures.
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Step 1

We have been given, a 0.533 M aqueous solution, means, the molarity is 0.533.

Molarity is the number of moles present per liter of the solution. 

Also, density = 1.059 g/mL.

We have to find out molality of the solution which is number of moles of solute present per kg of the solution.

Given solute is iron(II) Chloride 

Molar mass of solute = 127 g/mol 

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