Calculate the mean and 90% confidence interval for the data Sample Value set. Report your answer with the correct number of 1 5.0700 significant figures. 2 5.0620 3 5.0600 4 5.0630 5 5.0600 5.0580

You work for a soft-drink company in the quality control division.  You are interested in the standard deviation of one of your production lines as a measure of consistency. The product is intended to have a mean of 12 ounces, and your team would like the standard deviation to be as low as possible.  You gather a random sample of 18 containers.  Estimate the population standard deviation at a 95% level of confidence.   11.96 12.04 12.02 12.08 11.99 12.15 12.09 11.78 12.05 11.98 12.01 12.13 12.07 11.91 12.02 12.07 11.9 12.07   (Data checksum: 216.32) Note: Keep as many decimals as  possible while making these calculations. If possible, keep all answers exact by storing answers as variables on your calculator or computer. a)  Find the sample standard deviation:   b)  Find the lower and upper χ2χ2  critical values at 95% confidence:Lower:     Upper:  c)  Report your confidence interval for σσ:  (  ,  )

Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 90% confidence interval for p given that p = 0.9 and n 130. Round your answer for the point estimate to two decimal places, and your answers for the margin of error and the confidence interval to three decimal places. Point estimate = Margin of error = ± i The 90% confidence interval is i to i

#42

You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. A random sample of 45 home theater systems has a mean price of ​$114.00. Assume the population standard deviation is ​$15.30. Construct a​ 90% confidence interval for the population mean.

calculate the 95% confidence interval for the mean stock price of the firm assuming that the stock price is normally distibuted.

You work for a soft-drink company in the quality control division.  You are interested in the standard deviation of one of your production lines as a measure of consistency. The product is intended to have a mean of 12 ounces, and your team would like the standard deviation to be as low as possible.  You gather a random sample of 18 containers.  Estimate the population standard deviation at a 98% level of confidence.   11.98 11.99 11.96 12.09 11.79 11.96 11.87 12.1 12.16 12.03 12.04 12.11 12.12 12.15 11.95 12.23 11.95 12.12   (Data checksum: 216.6) Note: Keep as many decimals as  possible while making these calculations. If possible, keep all answers exact by storing answers as variables on your calculator or computer. a)  Find the sample standard deviation:   b)  Find the lower and upper χ2χ2  critical values at 98% confidence:Lower:     Upper:  c)  Report your confidence interval for σσ:  (  , )

You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals.   10. A random sample of 40 home theater systems has a mean price of ​$126.00. Assume the population standard deviation is ​$16.70. Construct a​ 90% confidence interval for the population mean.   The​ 90% confidence interval is ​(nothing​,nothing​)

The grade point averages for 10 randomly selected high school students are listed below. Assume the grade point averages are normally distributed. 2.0 3.2 1.8 2.9 0.9 4.0 3.3 2.9 3.6 0.8 a. Calculate a 90% confidence interval for the true mean grade point averages. b. The principal claims that a new after-school tutoring program has improved student GPAS to 3.0. Based on the confidence interval, is the principal telling the truth? Explain! c. What would happen to the confidence interval if the sample size was increased to 50 students? Be specific!