Calculate the mass of water that can be vaporized with 211 kJ of heat at the boiling point.

World of Chemistry, 3rd edition
3rd Edition
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Chapter14: Liquids And Solids
Section: Chapter Questions
Problem 14A
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Calculate the mass of water that can be vaporized with 211 kJ of heat at the boiling point.

Expert Solution
Step 1

Heat of water (q) = 211 KJ

Mass of water (m) = ?

• Heat is related with enthalpy of vaporization as given by formula :

q = m.∆Hvap  Or

m = q / ∆Hvap 

On multiply this value with molar mass of water, we can get mass of water. So,

m = (q / ∆Hvap ) × M

Where, 

q = heat of water ; m = mass of water.

∆Hvap = Enthalpy of vaporization of water & = 40.65 KJ/mol at 100°C (i.e boiling point)  ...(we know).

M = molar mass of water & = 18 g/mol  ...(we know).

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