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- SUPPOSE THE AMBIENT TEMPERATURE IS 20degrees CELSIUS, AND THE HOT RESERVOIR CONSISTS OF A SPHERICAL TANK WITH A RADIUS OF 4.00 m, THAT ACTS AS AN IDEAL EMITTER OF RADIATION. IF ALL THE RADIANT ENERGY EMITTED BY THE TANK COULD BE CAPTURED, WHAT IS THE AVERAGE AMOUNT OF WORK THAT COULD BE DONE EACH SECOND? ( please only answer if your 100% correct) (show work)4. The surface temperature of a planet is T, and the measured temperature is Tm (i.e. the temper- ature measured at the top-of-atmosphere based on the upwards flux Ft there). Assume radiative equilibrium. (a) Show that the infrared optical depth of the planet's surface 7 is related to the surface temperature T, and the measured temperature Tm by Calculate the infrared optical depth at the surfaces of (a) Earth, where T, = 300 K and Tm = 250 K. (b) Venus, where T, = 750 K and Tm = 230 K. (c) Mars, where T, = 240 K and T, = 220 K.The speed of sound in air is 340 m/s, and the speed of light is 3.0 X 108 m/s. What frequency oflight has the same wavelength as a 200.0 Hz sound wave?
- A long, horizontal, cylindrical steel reactor, 1 m in diameter, has a surface temperature of 300ºC. The emissivity of the steel is 0.6, and the heat transfer coefficient for natural convection is 5 W m−2 K−1 . Heat is lost by convection to the air at 15ºC, and also by radiation to the surroundings, which can be considered to be a black body at 15ºC. a) Calculate the total heat loss per metre length of the reactor, and the proportions lost by convection and radiation b) The reactor is then insulated with a thin layer of insulation material to reduce the total heat loss to one-tenth of its original value. This causes the surface temperature of the steel to rise to 400ºC. The thermal conductivity of the insulation is 0.01 W m−1 K−1 , and its surface emissivity is 0.2. Show that the resulting surface temperature of the insulation is about 89ºC, and calculate the thickness of insulation required, stating any assumptions made. Specifically need help with part bA long, horizontal, cylindrical steel reactor, 1 m in diameter, has a surface temperature of 300ºC. The emissivity of the steel is 0.6, and the heat transfer coefficient for natural convection is 5 W m−2 K−1 . Heat is lost by convection to the air at 15ºC, and also by radiation to the surroundings, which can be considered to be a black body at 15ºC. a) Calculate the total heat loss per metre length of the reactor, and the proportions lost by convection and radiation. b) The reactor is then insulated with a thin layer of insulation material to reduce the total heat loss to one-tenth of its original value. This causes the surface temperature of the steel to rise to 400ºC. The thermal conductivity of the insulation is 0.01 W m−1 K−1 , and its surface emissivity is 0.2. Show that the resulting surface temperature of the insulation is about 89ºC, and calculate the thickness of insulation required, stating any assumptions made. can you solve part b please?1. Solar Collector Problem: From the diameter of the sun and the earth and the mean distance of sun from earth, estimate (a) the amount of energy emitted from the sun, (b) the amount of energy received by the earth, and (c) the solar constant for a sun temperature of 5700K. If the distance of Planet-Y from the sun is 7.0 astronomical unit, estimate, (c) the solar constant for Planet-Y for a sun temperature of 5700K. (Stefan-Boltzmann constant, o = 5.67 x 10-8 W/m2-K4). Diameter of the sun = 1,392,000 km; DiaPlanet-y = 340,800 km; Mean distance of the sun from the earth = 149,600,000 km r Sun R 0₂ m Aa ||A₂ Ar Concentrator
- A pipe still uses 7110 lb per hour of a cracked gas (Net Heating Value (NHV) 20560 Btu per lb). The radiant section contains 1500 sq ft of projected area, and the tube (5 in. outside diameter) are spaced at a center-to-center distance of 10 in. there is only one row of radiant tubes, and they are 40 ft long. The ratio of air to fuel is (21 (30 percent excess air). a) What percentage of the heat liberation is absorbed in the radiant section? b) How many Btu are absorbed per hour through each square foot of projected area?T = 100 °C Vacuum T, = 20 °C Figure 1.17 Problem 1.12 Two walls facing each other are thin, very large in extent, highly conducting, and radiatively black on the facing surfaces (Fig. 1.17). They are separated by a vacuum. The outsides of the plates experi- ence convection (without radiation) as shown. Set up an equation for the temperature of the left-hand plate and solve it by iteration. Then find the temperature of the right-hand plate. [Tright = 42.5°C] h = 50 W/m?K h = 20 W/m?KThe tungsten filament of an incandescent light bulb has a temperature of approximately 3000 K. The emissivity of tungsten is approximately 1/3, and you may assume that it is independent of wavelength. To increase the efficiency of an incandescent bulb, would you want to raise or lower the temperature? (Some incandescent bulbs do attain slightly higher efficiency by using a different temperature.)
- A small sphere (emissivity = 0.745, radius = r1) is located at the center of a spherical asbestos shell (thickness = 1.72 cm, outer radius = r2; thermal conductivity of asbestos is 0.090 J/(s m Co)). The thickness of the shell is small compared to the inner and outer radii of the shell. The temperature of the small sphere is 727 °C, while the temperature of the inner surface of the shell is 406 °C, both temperatures remaining constant. Assuming that r2/r1 = 6.54 and ignoring any air inside the shell, find the temperature in degrees Celsius of the outer surface of the shell.Give step-by-step calculation and explanation Consider a person sitting nude on a beach in Florida. On a sunny day, visible radiation energy from the sun is absorbed by the person at a rate of 30 kcal/h or 34.9 W. The air temperature is a warm 30 °C and the individual’s skin temperature is 32 °C. The effective body surface exposed to the sun is 0.9 m². (Assume this same area for sun absorption, radiative transfer, and convective loss. Is this a good assumption?) a. Find the net energy gain or loss from thermal radiation each hour. (Assume thermal radiative gain and loss according to the equation 6.51 in Herman and an emissivity of 1.) -(4). Equalion (6.51) - (40Tin)Eskin Aşkin (Tskin – Troom) dt = (4 x 5.67 x 10¬8 w/m²–K* x (307 K)')€skin Askin (Tskin – Troom). (6.52) b. If there is a 4 m/s breeze, find the energy lost by convection each hour. (Use Eq. 6.61 with eq. 6.63.) 1 Equation he(Tskin – Tair), (6.61) A dt he 10.45 – w + 10w0.5 (6.63) - c. If the individual’s metabolic rate is…A west glass at (32 oN, August). With-2 interior shading SC=0.39 and Ug 4.3 W/m2. oC. The room temperature is (24 oC). Its dimensions are (5 x 1 m). At (17 PM) its direct solar heat gain rate is %3D اخترأحد الخيارات a. 678 W/m2 b. 174 W/m2 c. 691 W/m2 d. 663 W/m2