Calculate the enthalpy for this reaction 6C(s, gr) + 3H2(g) →CgHg(2) given the following information: 15 (1) C¿H6 () + – 02 (g) –→ 6CO2(g) + 3H2O() AH° = -3267 kJ (2) C(s, gr) + O2 (g) → CO2 (g) AH°= -393.5 kJ (3) H2 (g) + – O2 (g) → H20 (1) AH°= -285.83 kJ |

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Given the following two reactions:(1)Fe(s) + Cl2(g)->FeCl2(s) H(1) = -341.8 kJ(2)Hg(l) + Cl2(g)->HgCl2(s) H(2) = -224.3 kJcalculate the enthalpy change for the following reaction:(3) FeCl2(s) + Hg(l)-> Fe(s) + HgCl2(s) H(3) = kJ

Find the enthalpy change for this reaction using the data below. Clearly show how you got the answer. 2 Al(s) + 3 Cl2 (g) → 2 AlCl3 (s) Data: (a) 2 Al(s) + 6 HCl(aq) → 2 AlCl3 (aq) + 3 H2 (g)                     H = −1049 kJ (b) AlCl3 (s) → AlCl3 (aq)                                                             H = −323 kJ (c) H2 (g) + Cl2 (g) → 2 HCl(g)                                                    H = −185 kJ (d) HCl(aq) → HCl(g)                                                                     H = +74.8 kJ

（1）Consider the reaction: 2A (g) + 3 B (g) → 2 C (g)     ΔHrxn = +254.3 kJ What will be the enthalpy change (in kJ) if 0.471 mol B reacts in excess A?   （2）Consider the reaction: C (s) + O2 (g) → CO2 (g)     ΔHrxn = -393.5 kJ What mass of carbon (in g) must be reacted via this mechanism to release 581.2 kJ of heat?

In a coffee cup calorimeter, 3.00 g of NaOH (molar mass 40.00g/mol) was mixed with 75.0 mL of 1.00M HNO3. If the initial temperature of the HNO3 was 31.3°C and the final temperature of the solution was 22.3°C, determine AH for the reaction in kJ/mol. NaOH(s) + HNO3(aq) ===> NaNO3(aq) + H2O) The density and the specific heat capacity of the resulting solution are 1.00 g/ml and 4.18 J/°C.g, respectively. Units do not need to be typed, simply enter the correct number. If the sign of AH is negative put a negative sign (-) in the answer. Answer: