Calculate the energy released by the fission of 5 gm of 235U in kWh if energy released per fission is 200 MeV. a) 1.13 X 105 kWh b) 2.65 X 105 kWh c) 3.78 X 105 kWh d) 4.12 X 105 kWh

A nucleus of 238 Np captures a thermal neutron to form a nucleus of 239 Np . What is the excitation energy ( to 1 dp ) in MeV for this process ?

9 H the mass of the products in a fission reaction is 3.2 x 10^28 kg less than the reactants, how much energy is released in the reaction? (A) 3.6 10 45J (B) 1.1 x 10-38J (C) 9.6 x 10420 J (D) 2.9 x 10-11 J

One of the ways that 235U can fission is by means of the following reaction: In +235 U 141 Ba + Kr + 3 n 56 Atomic masses of the reactants and products are as follows: n 235 U 92 92 Kr 36 141 Ba 56 1.008665 u 235.043930 u 91.926156 u 140.9144035 u a) Determine the energy in MeV that is released when one 23592U nucleus fissions. Assume that the incoming neutron is very slow. b) Find the total energy released in MeV if 2.8 kg of 23592U were to undergo fission entirely by this reaction.