Calculate E cell and indicate whether the overall reaction shown is spontaneous or nonspontaneous. H202(aq) + 2H*(aq) + 2e¯ = 2H2O(); E° = 1.77 V Fe*(aq) + e = Fe2*(aq); E° = 0.77 V Overall reaction: 2Fe*(aq) + 2H20() → H202(aq) + 2H*(aq) + 2Fe²+(aq) E° cell = +1.00 V, nonspontaneous E cell =-1.00 V, nonspontaneous E cell = +1.00 V, nonspontaneous O E° cell =-1.00 V, spontaneous
Calculate E cell and indicate whether the overall reaction shown is spontaneous or nonspontaneous. H202(aq) + 2H*(aq) + 2e¯ = 2H2O(); E° = 1.77 V Fe*(aq) + e = Fe2*(aq); E° = 0.77 V Overall reaction: 2Fe*(aq) + 2H20() → H202(aq) + 2H*(aq) + 2Fe²+(aq) E° cell = +1.00 V, nonspontaneous E cell =-1.00 V, nonspontaneous E cell = +1.00 V, nonspontaneous O E° cell =-1.00 V, spontaneous
Chemistry by OpenStax (2015-05-04)
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Chapter16: Thermodynamics
Section: Chapter Questions
Problem 37E: Consider the decomposition of red mercury(II) oxide under standard state conditions.....
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Transcribed Image Text:QUESTION 31
Calculate Ecell and indicate whether the overall reaction shown is spontaneous or nonspontaneous.
E° = 1.77 V
H202(aq)
+ 2H*(aq) + 2e = 2H20();
Fe3+(aq) + e = Fe2*(aq);
E° = 0.77 V
Overall reaction:
2FE3*(aq) + 2H20() – H202(aq) + 2H*(aq) + 2Fe2+(ag)
E cell = +1.00 V, nonspontaneous
E cell =-1.00 V, nonspontaneous
E° cell = +1.00 V, nonspontaneous
E cell =-1.00 V, spontaneous
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