Calculate AS for the transformation n. Ice at 273K and 1 atm 423K y 1.1atm Data: C (H₂O) = 75.291 2 (') Р ΔΗ C (H₂O) = 33,577- P 2 (g) ΔΗ fits vap kJ mol = 6.0095- → steam at J molk J. molk = 40.6563- kJ mol

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question
Calculate AS for the transformation
n.
Ice at 273K and 1 atm →
423K y 1.1atm
Data:
С (НО
C₁ (H₂00)
Р
= 75.291
C (H₂O) = 33,577-
Р
2 (g)
ΔΗ
ΔΗ
fits
vap
kJ
mol
= 6.0095-
J
molk
J.
molk
kJ
mol
= 40.6563-
steam at
Transcribed Image Text:Calculate AS for the transformation n. Ice at 273K and 1 atm → 423K y 1.1atm Data: С (НО C₁ (H₂00) Р = 75.291 C (H₂O) = 33,577- Р 2 (g) ΔΗ ΔΗ fits vap kJ mol = 6.0095- J molk J. molk kJ mol = 40.6563- steam at
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