Calculate AH (kJ/mol) , enthalpy of formation, for the hypothetical CaF(s) given: AHlattice = -895 kJ/mol AHsub(Ca) = +178 kJ/mol AHje1 (Ca) = +590 kJ/mol AHje2 (Ca) = +1250 kJ/mol AH«(F2) = +158 kJ/mol AHea(F) = -328 kJ/mol O 1053 O -974 O 974

Calculate AH (kJ/mol) , enthalpy of formation, for the hypothetical CaF(s) given: AHlattice = -895 kJ/mol AHsub(Ca) = +178 kJ/mol AHje1 (Ca) = +590 kJ/mol AHje2 (Ca) = +1250 kJ/mol AH«(F2) = +158 kJ/mol AHea(F) = -328 kJ/mol O 1053 O -974 O 974

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

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Calculate AH; (kJ/mol) , enthalpy of
formation, for the hypothetical CaF(s)
given:
AHlattice = -895 kJ/mol
AHsub(Ca) = +178 kJ/mol
AHje1 (Ca) = +590 kJ/mol
AHje2 (Ca) = +1250 kJ/mol
AHd(F2) = +158 kJ/mol
AHea(F) = -328 kJ/mol
1053
-974
974
874
O -1053

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