CaCl,*2H,O(aq) + Na,CO3 (a4) → 2NaCl + CaCO3 () + 2H,0 (aq) 1 mole Cacl,"2H,O 2 mole NacI 58.44g NaCI 5.0 g CaCl,*2H,O x 3.97g Naci 147.02g cacı,"2H,0 1 mole cacı,"2H,0 1 mole Naci 1 mole Na,CO, 58.44g Naci X 2 mole Naci 5.0 g Na,Co, x = 5.51g Naci 105.99 g Na,CO, 1 mole Na,Co, 1 mole Naci 3.97g is the Theoretical Yield of the Precipitate.

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Do you agree with the work above that the Theoretical Yield of the precipitate is 3.97g? 
 
A) Yes, but I would need to know the Actual Yield to know how close we got to the correct answer
 
B) No, NaCl is not the precipitate so this does not give you an accurate Theoretical Yield of the precipitate
 
C) No, the molar mass for Calcium Chloride Dihydrate is 110.98g
 
D) Yes, 3.97 g is the correct Theoretical Yield of the Precipitate
 
E) No, 5.51 g is the correct Theoretical Yield of the Precipitate
CaCl,*2H,O(aq) + Na,CO3 (a4) → 2NaCl
+ CaCO3 () + 2H,0
(aq)
1 mole Cacl,"2H,O
2 mole NacI
58.44g NaCI
5.0 g CaCl,*2H,O x
3.97g Naci
147.02g cacı,"2H,0
1 mole cacı,"2H,0
1 mole Naci
1 mole Na,CO,
58.44g Naci
X
2 mole Naci
5.0 g Na,Co, x
= 5.51g Naci
105.99 g Na,CO, 1 mole Na,Co,
1 mole Naci
3.97g is the Theoretical Yield of the Precipitate.
Transcribed Image Text:CaCl,*2H,O(aq) + Na,CO3 (a4) → 2NaCl + CaCO3 () + 2H,0 (aq) 1 mole Cacl,"2H,O 2 mole NacI 58.44g NaCI 5.0 g CaCl,*2H,O x 3.97g Naci 147.02g cacı,"2H,0 1 mole cacı,"2H,0 1 mole Naci 1 mole Na,CO, 58.44g Naci X 2 mole Naci 5.0 g Na,Co, x = 5.51g Naci 105.99 g Na,CO, 1 mole Na,Co, 1 mole Naci 3.97g is the Theoretical Yield of the Precipitate.
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