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Compound
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- NH2 A B Proton NMR: 2.7 (triplet, 2H), 1.7 (nonet, 1H), 1.5 (quintet, 2H), 1.4 (broad singlet, 2H), 1.2 (quartet, 2H), 0.9 (doublet, 6H) Carbon-13 NMR: 44, 37, 30, 28, 23 IR (below): D 4D00 3000 2000 1500 1000 500 HAVENUMB ERI I-Z I-Z TRANSHETTANCEIH,CO A B C H. E D Proton NMR: 7.1 (doublet, 2H), 6.9 (doublet, 2H), 4.0 (quartet, 2H), 3.5 (singlet, 2H), 2.2 (singlet, 3H), 1.3 (triplet, 3H) Carbon-13 NMR: 205, 157, 130, 126, 114, 65, 49, 30, 15 IR (below): Note that none of the choices has an O-H group, so the peak at 3500 must be for water impurity? LOD D 4D00 3000 2000 1500 1000 50 NAVENUMBERI -1 TRANSHETTANCEI2) Propose structures for the compounds with the following data. Molecular Data Answer formula unit IR: 3400 cm'(broad), 3250 cm (sharp), 2150 cm-1 'H NMR ppm: 1.0 (t, 3H), 1.5 (s, 3H), 1.6 (q, 2H), 2.0 (s, 1H), 2.5 (s, 1H) 13C NMR: 4.1, 26, 35, 67.6, 69.4 C6H100 hangi don tor liw ob IR: 1680 cm', 2750 cm1, 2850 cm 'H NMR ppm: 1.1 (t, 3H), 3.5 (q, 2H), 4.5 (s, Jeg of griquo 2H), 7.3 (d, 2H), 7.7 (d, 2H), 9.9 (s, 1H) G ebacc bLOAigeq C10H12O2 -1 100 gmi sa oy bloow ooge orit ni C4H100 IR: Strong peak around 3500 cm-1 'H NMR: 1.28, (s, 9H), 1.35 (s, 1H) 3) Give three UNIQUE syntheses of benzylamine starting from benzene.
- 1H-nmr signal at 4.2 (d) is due to * 'H NMR Spectrum exchanges with D;0 (200 MHz. CDCI, solution) expansion Expansion 7.0 6.2 ppm 38 3.0 ppm TMS 10 8 7 6 4 3 1 8 (ppm) OH -OCH2 aliphatic C-H Aromatic CH3 aliphatic vinylic HIdentify the structures of isomers A (molecular formula C9H10O).Compound A: I R peak at 1742 cm−1; 1H NMR data (ppm) at 2.15 (singlet, 3H), 3.70 (singlet, 2 H), and 7.20 (broad singlet, 5 H).Add Ink to Ink to Drawing Canvas Pen Shape Math Comvert Insert CHICHOBENICOCE 2 3C S 13 15 16 (Complete the mind map given Observation: veddish brown of Brs deolounzed -Br Br CH,CI, Br2, H20 Cl2, CIA HBr H;C H,O, H,o H2, Pt conc. H,SO, H2C CH CHS он dilute KMno . OH- heat 4+ CH2 CH2 HCI + mn Oz HCI, H,O Her, CH,0OCH, observation: purple cSlour Br, CI, Cl,, H,O dikúte H, So, 5 yvees ENG US
- H NH2 A B D E Proton NMR: 2.7 (quartet, 2H), 2.5 (doublet, 2H), 1.7 (nonet, 1H), 1.6 (broad singlet, 1H), 1.1 (triplet, 3H), 0.9 (doublet, 6H) Carbon-13 NMR: 58, 45, 29, 21, 16 IR (below): LOD D 4000 3000 2000 1500 1000 500 HAVENUMBERI -1 TRANSMETTANCEI I-ZUsing 'H NMR Spectroscopy to Distinguish between Compounds Provide a structure that is consistent with the data below. C7H160 IR (cm 1): 3200-3600 (broad), 2950 H NMR ( delta, ppm): 2.8 (1H, broad s), 1.4 (6H, s), 0.9 (9H, s) HO, OH C OB Oc OAThe proton NMR spectrum for a compound with formula C10H12O2is shown below.The infrared spectrum has a strong band al 1711 cm-1. The normal carbon-13 NMRspectral results are tabulated along with the DEPT-135 and DEPT-90 information. Drawthe structure of this compound.
- Which structure is in agraement with both of thasa R and H NMA data? IR, cm (Intensity)-2965 (strong), 1745 (strong), 1238 (strong) H NMR, ppm (splitting, H): 0.94 (doublet, 6H), 193 (multiplet, 1H), 2.05 (singlet, 3H), 3.8as (doublet, 2H) A. tor B. D. C.Determine the structure of a compound based on the data given below. IR: 3200-35oocm-1 Mass: 74 (M+), 59 (100%), 56, 45 1H NMR: d 4.0 (bs, 1H), 3.5 (ddq, 1H), 1.5 (ddq, 1H), 1.4 (ddq, 1H), 1.0 (d, 3H), 0.9 (d, 3H)3. A compound with the following 'H NMR spectrum has a molecular formula of C6H11N, from the data how many protons inI and how many protons in II?