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(c) What is the overall reaction? (Use the lowest possible whole number coefficients. Omit states-of-matter in your answer.) chemPad Help XX→→ 2A + EF 2A+ E-> F Correct. Greek

(c) What is the overall reaction? (Use the lowest possible whole number coefficients. Omit states-of-matter in your answer.) chemPad Help XX→→ 2A + EF 2A+ E-> F Correct. Greek

Chemistry for Engineering Students
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter11: Chemical Kinetics
Section: Chapter Questions
Problem 11.41PAE: 11.41 For a drug to be effective in treating an illness, its levels in the bloodstream must be...
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Just the final part that is incorrect.

Consider the following three-step mechanism: i) 2A → B + C fast ii) C + B →D slow iii) D + E F fast (a) What is the molecularity of each step? Step (i):[bimolecular Step (ii): bimolecular Step (iii): bimolecular (b) Identify any intermediate(s). (Select all that apply.) OA ✔B с ✔D DE (c) What is the overall reaction? (Use the lowest possible whole number coefficients. Omit states-of-matter in your answer.) chemPad Help XX 2A + E → F 2A+ E--> F Correct. Greek (d) What is the rate law? (Rate equations take the general form 'rate = k. [A] . [B]'.) chemPad Help XX rate = k [A]² [E] rate = k [A]^2 [E] Your answer appears to contain too many substances. Greek
Transcribed Image Text:Consider the following three-step mechanism: i) 2A → B + C fast ii) C + B →D slow iii) D + E F fast (a) What is the molecularity of each step? Step (i):[bimolecular Step (ii): bimolecular Step (iii): bimolecular (b) Identify any intermediate(s). (Select all that apply.) OA ✔B с ✔D DE (c) What is the overall reaction? (Use the lowest possible whole number coefficients. Omit states-of-matter in your answer.) chemPad Help XX 2A + E → F 2A+ E--> F Correct. Greek (d) What is the rate law? (Rate equations take the general form 'rate = k. [A] . [B]'.) chemPad Help XX rate = k [A]² [E] rate = k [A]^2 [E] Your answer appears to contain too many substances. Greek
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