c++ please. code to solve a quadratic equation (a,b,c entered and solution outputed). please include comments to walk through code.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Write in c++ please. code to solve a quadratic equation (a,b,c entered and solution outputed). please include comments to walk through code.

• Case of a quadratic equation with a single solution:
Type a real number a:
Туре а reеal number b: 4
Type a real number c:
4
X = -2
%3D
• Case of a quadratic equation with no real solution:
Туре а real number a:
1
Туре а real number b: 2
Туре а real number c: 5
No real solution
Transcribed Image Text:• Case of a quadratic equation with a single solution: Type a real number a: Туре а reеal number b: 4 Type a real number c: 4 X = -2 %3D • Case of a quadratic equation with no real solution: Туре а real number a: 1 Туре а real number b: 2 Туре а real number c: 5 No real solution
• Case with all reals as solutions:
Туре а real number a: 0
Туре а real number b: 0
Туре а real number c:
All solutions
• Case of linear equation with no solution:
Туре а real number a:
Туре а real number b: 0
Туре а real number c: 2
No solution
• Case of linear equation with a single solution:
Туре а real number a:
Туре а real number b: 2
Туре а real number c: 3
х%3D -1.5
• Case of a quadratic equation with two solutions:
Туре а reеal number a: 2
Туре а real number b: -5
Туре а real number c: -12
х1 %3
4, х2 %3D -1.5
Transcribed Image Text:• Case with all reals as solutions: Туре а real number a: 0 Туре а real number b: 0 Туре а real number c: All solutions • Case of linear equation with no solution: Туре а real number a: Туре а real number b: 0 Туре а real number c: 2 No solution • Case of linear equation with a single solution: Туре а real number a: Туре а real number b: 2 Туре а real number c: 3 х%3D -1.5 • Case of a quadratic equation with two solutions: Туре а reеal number a: 2 Туре а real number b: -5 Туре а real number c: -12 х1 %3 4, х2 %3D -1.5
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