c) d² y dt² +2+y=4t, y(0) = 0, y'(0)=5 dt
Trigonometry (MindTap Course List)
10th Edition
ISBN:9781337278461
Author:Ron Larson
Publisher:Ron Larson
Chapter6: Topics In Analytic Geometry
Section6.2: Introduction To Conics: parabolas
Problem 4ECP: Find an equation of the tangent line to the parabola y=3x2 at the point 1,3.
Related questions
Question
5c
![5. Solve the equation subject to the given conditions.
d'y dy
dt
-6y=5e', y(0) = 0, y'(0)=1
dt²
a)
b)
c)
d)
e)
f)
d'y
dt²
h)
d² y
dt²
d² y
dt²
dy
dt
dy
+2. - + y = 4t, y(0) = 0, y'(0)= 5
dt
-6y=4e², y(0) = 1, y'(0)= 4
d² y
dt²
-6y=5U, (t), y(0) = 2
+4y= te³¹, y(0) = 0, y'(0)=1
d² y
dt²
d'y
g) --y=U₁(t)-U₂ (t), y(0) = 0, y'(0)=2
dt²
- y = U₁(t), y(0) = 1, y'(0) = 4
+y = t-U₁(t)(t-1), y(0) = 1, y'(0)=1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4d410cd6-8fc6-4d13-8ff0-7a43ba3056bc%2F30713117-0ee0-4ace-895f-b371d98ffebf%2F06ajjan_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5. Solve the equation subject to the given conditions.
d'y dy
dt
-6y=5e', y(0) = 0, y'(0)=1
dt²
a)
b)
c)
d)
e)
f)
d'y
dt²
h)
d² y
dt²
d² y
dt²
dy
dt
dy
+2. - + y = 4t, y(0) = 0, y'(0)= 5
dt
-6y=4e², y(0) = 1, y'(0)= 4
d² y
dt²
-6y=5U, (t), y(0) = 2
+4y= te³¹, y(0) = 0, y'(0)=1
d² y
dt²
d'y
g) --y=U₁(t)-U₂ (t), y(0) = 0, y'(0)=2
dt²
- y = U₁(t), y(0) = 1, y'(0) = 4
+y = t-U₁(t)(t-1), y(0) = 1, y'(0)=1
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