C) Calculate the change in internal energy in each process, the change in total internal energy and complete the following table. Internal Energy AU(J) Process Work W(J) Heat Q(J) a→ b b → c c+ d d → a

Physical Chemistry
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ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
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Chapter2: The First Law Of Thermodynamics
Section: Chapter Questions
Problem 2.65E: A sample of an ideal diatomic gas is compressed adiabatically and reversibly to double its initial...
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C2) Answer the question shown in the image 

C) Calculate the change in internal energy in each process, the change in total
internal energy and complete the following table.
Process
Internal
Work W(J)
Heat Q(J)
Energy AU(J)
a→ b
c + d
d → a
Transcribed Image Text:C) Calculate the change in internal energy in each process, the change in total internal energy and complete the following table. Process Internal Work W(J) Heat Q(J) Energy AU(J) a→ b c + d d → a
Consider 0.910 mol of an ideal diatomic gas that undergoes the described
thermodynamic cycle:
•a - b: an isobaric expansion starting with a volume V, = 1.00 x 10?m³
Until the volume doubles
c: isochoric heating up to tripling its pressure and reaching a temperature of
1000 K.
•c- d: an isothermal compression until reaching a pressure of 5.361x107 Pa.
•d -
→ a: an adiabatic expansion until returning to the starting point.
Also, consider the following table
State
Volume (m³)
Pressure ( Pa)
Tempentue)
1-013 X105
166 66 7k
a
I X10
2 x102
1.013 X1o5
333-333k
2 x 102
3-039 xro5
1000K
100ok
1:34 X104
5.361 X10?
Transcribed Image Text:Consider 0.910 mol of an ideal diatomic gas that undergoes the described thermodynamic cycle: •a - b: an isobaric expansion starting with a volume V, = 1.00 x 10?m³ Until the volume doubles c: isochoric heating up to tripling its pressure and reaching a temperature of 1000 K. •c- d: an isothermal compression until reaching a pressure of 5.361x107 Pa. •d - → a: an adiabatic expansion until returning to the starting point. Also, consider the following table State Volume (m³) Pressure ( Pa) Tempentue) 1-013 X105 166 66 7k a I X10 2 x102 1.013 X1o5 333-333k 2 x 102 3-039 xro5 1000K 100ok 1:34 X104 5.361 X10?
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