But if the original square had an initial surface of S2 =1 sq units, that is, side of 1 times side of 1 = 1 sq unit, how can the resulting shape, that is, distorting a square to form a hyperbolic paraboloid, have a surface area of 5.708 sq units??

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Thanks for prompt response. But if the original square had an initial surface of S² =1 sq units, that is, side of 1 times side of 1 = 1 sq unit, how can the resulting shape, that is, distorting a square to form a hyperbolic paraboloid, have a surface area of 5.708 sq units??

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Is it pi/8 times the square root of 2 to the 3rd power, that is 8, minus one in that order??

Using that sequence i don't get 1.166

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Is it pi/8 times the square root of 2 to the 3rd power, that is 8, minus one in that order??

Using that sequence i don't get 1.166

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Is it pi/8 times the square root of 2 to the 3rd power, that is 8, minus one in that order??

Using that sequence i don't get 1.166

Solution

by Bartleby Expert

SEE SOLUTION

Answer 21

Follow-up Question

Is it pi/8 times the square root of 2 to the 3rd power, that is 8, minus one in that order??

Using that sequence i don't get 1.166

Solution

by Bartleby Expert

SEE SOLUTION

Answer 22

Follow-up Question

Is it pi/8 times the square root of 2 to the 3rd power, that is 8, minus one in that order??

Using that sequence i don't get 1.166

Answer 23

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Answer 24

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Answer 25

Is it pi/8 times the square root of 2 to the 3rd power, that is 8, minus one in that order??

Using that sequence i don't get 1.166

Answer 26

Is it pi/8 times the square root of 2 to the 3rd power, that is 8, minus one in that order??

Using that sequence i don't get 1.166

Answer 27

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Follow-up Questions

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Follow-up Question

Is it pi/8 times the square root of 2 to the 3rd power, that is 8, minus one in that order??

Using that sequence i don't get 1.166

Solution

by Bartleby Expert

SEE SOLUTION

Answer 33

Read through expert solutions to related follow-up questions below.

Follow-up Question

Is it pi/8 times the square root of 2 to the 3rd power, that is 8, minus one in that order??

Using that sequence i don't get 1.166

Solution

by Bartleby Expert

SEE SOLUTION

Answer 34

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Answer 35

Follow-up Question

Is it pi/8 times the square root of 2 to the 3rd power, that is 8, minus one in that order??

Using that sequence i don't get 1.166

Solution

by Bartleby Expert

SEE SOLUTION

Answer 36

Follow-up Question

Is it pi/8 times the square root of 2 to the 3rd power, that is 8, minus one in that order??

Using that sequence i don't get 1.166

Solution

by Bartleby Expert

SEE SOLUTION

Answer 37

Follow-up Question

Is it pi/8 times the square root of 2 to the 3rd power, that is 8, minus one in that order??

Using that sequence i don't get 1.166

Answer 38

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Answer 39

Follow-up Question

Answer 40

Is it pi/8 times the square root of 2 to the 3rd power, that is 8, minus one in that order??

Using that sequence i don't get 1.166

Answer 41

Is it pi/8 times the square root of 2 to the 3rd power, that is 8, minus one in that order??

Using that sequence i don't get 1.166

Answer 42

Solution

by Bartleby Expert

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Answer 43

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Answer 45

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Answer 46

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But if the original square had an initial surface of S2 =1 sq units, that is, side of 1 times side of 1 = 1 sq unit, how can the resulting shape, that is, distorting a square to form a hyperbolic paraboloid, have a surface area of 5.708 sq units??

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