A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y = 4 –- 2°. What are the dimensions of such a rectangle with the greatest possible area? Width = Height =

Find the maximum area of a rectangle that is inside of the triangle formed by the x-axis and the lines y=-3x + 12 and y = 3x + 12. The base of the rectangle is on the x-axis and the two upper vertices are on the lines y=-3x + 12 and y = 3x + 12 as shown in the illustration.

Arrange the parabolas represented by the equations according to the positions of their foci on the coordinate plane, starting with the farthest left and ending with the farthest right. y = 56(+2+4x–1,628) 0+18y-647) *+12y-76) y = (z?+22r+73} I= 1(v? 10y-231) 1=(2-14y-239) entum. All rights reserved. MacBook Air FIO II ER F9 F7 20 F3 D00 F4 F5 F2

rectangle is constructed with its base on the​ x-axis and two of its vertices on the parabola y=144−x2. What are the dimensions of the rectangle with the maximum​ area? What is the​ area? The shorter dimension of the rectangle is nothing and the longer dimension is nothing.