Blood is accelerated from rest to 125 cm/s in a distance of 0.3125 cm by the left ventride of the heart. Find its acceleration, and how long does the acceleration take? O a. a 500 cm/s^2 and t= 0.05 s O b. a 500 cm/s^2 and t= 0.12 s Oc a 250 cm/s^2 and t 0.12 s O d. a= 250 cm/s^2 and t = 0.05 s a%3D
Blood is accelerated from rest to 125 cm/s in a distance of 0.3125 cm by the left ventride of the heart. Find its acceleration, and how long does the acceleration take? O a. a 500 cm/s^2 and t= 0.05 s O b. a 500 cm/s^2 and t= 0.12 s Oc a 250 cm/s^2 and t 0.12 s O d. a= 250 cm/s^2 and t = 0.05 s a%3D
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![Blood is accelerated from rest to 125 cm/s in a distance of 0.3125 cm by the left ventride of the heart. Find its acceleration, and how
long does the acceleration take?
O a. a= 500 cm/s^2 and t= 0.05 s
O b. a= 500 cm/s^2 and t = 0.12 s
a = 250 cm/s^2 andt = 0.12 s
O d. a= 250 cms^2 and t = 0.05 s
What would be the equilibrium potential for the ion K+ in a cell be if (K+Jout= 4 mM and [K+ in= 155 mM? Giver: R = 8.314472
J/mol.K. T= 37C = 310 K, F = 9.65 * 10^4 C/mol
O a. + 66.5 mV
O b. +128.3 mV
- 90.8 mv
- 98 mV](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdcdc9598-ca02-4a93-a92e-f84bcd16c714%2F314683e7-1697-4864-9cc6-ab2b1e65a19d%2Fsoktcz_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Blood is accelerated from rest to 125 cm/s in a distance of 0.3125 cm by the left ventride of the heart. Find its acceleration, and how
long does the acceleration take?
O a. a= 500 cm/s^2 and t= 0.05 s
O b. a= 500 cm/s^2 and t = 0.12 s
a = 250 cm/s^2 andt = 0.12 s
O d. a= 250 cms^2 and t = 0.05 s
What would be the equilibrium potential for the ion K+ in a cell be if (K+Jout= 4 mM and [K+ in= 155 mM? Giver: R = 8.314472
J/mol.K. T= 37C = 310 K, F = 9.65 * 10^4 C/mol
O a. + 66.5 mV
O b. +128.3 mV
- 90.8 mv
- 98 mV
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