Below is the Lewis structure of the hydrogen peroxide H2O2 molecule.  Count the number of bonding pairs and the number of lone pairs around the right oxygen atom.

Consider an iodine tetrafluoride cation (IF4+): What is the elemental symbol of its central atom? How many valence electrons does this molecule contain? How many lone electron pairs surround the central atom? How many regions of electron density surround the central atom? For remaining items in this question, place the appropriate letter in the box: What is the electron geometry of this molecule? A = linear B = trigonal planar C = tetrahedral D = trigonal bipyramidal E = octahedral   What is the molecular shape of this molecule? A = tetrahedral B = trigonal pyramid C = bent or angular D = T-shape E = Sawhorse or seesaw   Is this a polar molecule? A = Yes B = No What is the hybridization of the central atom? A = sp B = sp2  C = sp3  D = sp3d  E = sp3d2

Although carbon has four bonds in stable molecules, sometimes reactive carbon intermediates that contain carbon atoms without four bonds are formed for very short time periods. Examples of these unstable intermediates include the methyl carbocation (CH 3) + and the methyl carbanion (CH 3) −. Draw Lewis structures for both unstable ions and predict the shape around carbon.

Decide whether these proposed Lewis structures are reasonable. proposed Lewis structure a=ö] [[:N_N=N]] Yes. Is the proposed Lewis structure reasonable? No, it has the wrong number of valence electrons. The correct number is: No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are: Yes. No, it has the wrong number of valence electrons. The correct number is: No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are:* ☐ Yes. No, it has the wrong number of valence electrons. The correct number is: No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are:* *If two or more atoms of the same element don't satisfy the octet rule, just enter the chemical symbol as many times as necessary. For example, if two oxygen atoms don't satisfy the octet rule, enter "0,0".