Below is a graph of a normal distribution with mean μ = -5 and standard deviation o=3. The shaded region represents the probability of obtaining a val from this distribution that is greater than -2. 03+ 02+ 04+ Shade the corresponding region under the standard normal curve below. 0.1+ 03- 02+ X 5

A population forms a normal distribution with a mean of 85 and a standard deviation of 24 compute the Z score for the sample mean M equals 91 for N equals 16 scores Z equals what

A normal distribution has a mean of μ = 100 with σ = 20. If one score is randomly selected from this distribution, what is the probability that the score will have a value between X = 100 and X = 130?

Below is a graph of a normal distribution with mean μ--3 and standard deviation o=2. The shaded region represents the probability of obtaining a value from this distribution that is greater than -5. -4 -3 -2 Shade the corresponding region under the standard normal curve below. -1 0.4- 0.3- 0.2+ 0.4+ 0.1+ 0.3- 0.2+ 0.1+ 2 3 4 N 5

A normal distribution has a mean of µ = 100 with σ = 20. If one score is randomly selected from this distribution, what is the probability that the score will have a value between X = 90 and X = 110?​

In a Normal Distribution with the Mean of 77 and the Standard Deviation of 5 , find P ( x>66)

4. (Normal Distribution) Setup: Define za to be a z-score with an area of a to the right. For example: 20.10 means P(Z > 20.10) = 0.10. We would also have, for example: P(Z Z) = 0.057. Hint: It may help to draw a picture of what you want to find. Zo.10 1 I P(Z > Zo.10) 0.10 L

(a) The graph shows a Standard Normal Distribution. You are given 1 or 2 z-score(s) and need to shade the area (=probability) corresponding to: Р(г < 1.6). Click on the "Shade" menu to select the shading option corresponding to the question [to the left, to the right, or between 2 values]. Then slide the arrow to the appropriate z-score. Shade: Left of a value v. Click and drag the arrows to adjust the values. -3 -2 -1 2 4 -1.5 (b) Part 2: you are given an area (=probability), and you need to compute c, which is the z-score that corresponds to the statement: P(z < c) = 0.4 (This is an inverse standard normal distribution problem. Use technology to compute c) The arrow can only be dragged to tick marks that are multiples of 0.1 So, round c to 1 decimal place, and then move the arrow to that rounded value. Click on the "Shade" menu to select the shading option corresponding to the question [to the left, to the right, or between 2 values]. (If the question is less c, choose Left of a…

Fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean ? = 27.1 kilograms and standard deviation ? = 4.0 kilograms. Let x be the weight of a fawn in kilograms.

The lengths of pregnancies in a small rural village are normally distributed with a mean of 261 days and a standard deviation of 17 days. What percentage of pregnancies last fewer than 314 days? P(x < 314 days) = P(z<