Below, enter code to complete implementation of a recursive function Sum alLintegers(), which takes an input n and adds all integers preceding it, up to n: add all integers(n):

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Data Structures and Algorithms in C/C++ a) Implement the addLargeNumbers function with the following prototype: void addLargeNumbers(const char *pNum1, const char *pNum2); This function should output the result of adding the two numbers passed in as strings. Here is an example call to this function with the expected output: /* Sample call to addLargeNumbers */ addLargeNumbers("592", "3784"); /* Expected output */ 4376 b)  Implement a test program that demonstrates adding at least three pairs of large numbers (numbers larger than can be represented by a long). c) (1 point) Make sure your source code is well-commented, consistently formatted, uses no magic numbers/values, follows programming best-practices, and is ANSI-compliant.

Consider the following recursive function:   void recurse(int num) {   if (num == 0)     cout << “ Zero” << endl;   else {     cout << " " << num << " " << endl;     recurse(num + 1)   } }       Is recurse (-2) a valid call? If a valid call, what is the output of the entire function execution? If not a valid call, explain why it is not a valid call.

I need the code from start to end with no errors and the explanation for the code ObjectivesJava refresher (including file I/O)Use recursionDescriptionFor this project, you get to write a maze solver. A maze is a two dimensional array of chars. Walls are represented as '#'s and ' ' are empty squares. The maze entrance is always in the first row, second column (and will always be an empty square). There will be zero or more exits along the outside perimeter. To be considered an exit, it must be reachable from the entrance. The entrance is not an exit.Here are some example mazes:mazeA7 9# # ###### # #   ## # # #### #     ## ##### ##       ########## RequirementsWrite a MazeSolver class in Java. This program needs to prompt the user for a maze filename and then explore the maze. Display how many exits were found and the positions (not indices) of the valid exits. Your program can display the valid exits found in any order. See the examples below for exact output requirements. Also, record…

Write a function lis_rec(arr) that outputs the length of the longest increasing sequence and the actual longest increasing sequence. This function should use divide and conquer strategy to the solve the problem, by using an auxiliary function that is recursive. For example, one possibility is to define a recursive function, lis_rec(arr, i, prev), that takes the array arr, an index i, and the previous element index prev of LIS (which is part of the array arr before index i), and returns the length of the LIS that can be obtained by considering the subarray arr[i:]. Write a dynamic programming version ofthe function, lis_dp(arr), that outputs the length of the longest increasing sequence and the actual longest increasing sequence by using a table to store the results of subproblems in a bottom-up manner. Test the performance of the two functions on arrays of length n = 100, 500, 1000, 5000, 10000. Compare the running times and memory usage of the two functions.

Below is the recursive implementation of binary search from lab with one change (in red): the print statement at the top of the function which prints "BOO" There is also a main function which calls bsearchR on the sorted array data[] with 7 elements and searching for 10. QUESTION: How many BOOS will be printed by this program? // Recursive Binary Search Routine that does the "Real" Work int bsearchR(int a[], int lo, int hi, int x) { int m; printf("BO0\n"); // <<<<==== NEW STATEMENT if(hi < lo) return -1; m = (lo + hi) / 2; if(a[m] == x) return m; else if(x < a[m]) return bsearchR(a, lo, m-1, x); else return bsearchR(a, m+1, hi, x); } int main() { int data[] = {5, 8, 12, 15, 20, 25, 30}; int idx = bsearchR(data, e, 6, 10); return 0; }