One remarkably simple formula for calculating the value of p is the so-called Madhava-Leibniz series: p4 = 1-13+15-17+19-... . Consider the recursive function below to calculate the first n terms of this formula: double computePI (int n) { if (n <= 1) { return 1.0;} int oddnum = 2 * n

Consider a recursive function, called f, that computes powers of 3 using only the + operator. Assume n > = 0. int f(int n) { if (n == 0) return 1; return f(n-1) + f(n-1) + f(n-1); } Give an optimized version of f, called g, where we save the result of the recursive call to a temporary variable t, then return t+t+t. i got int g(int n) { if (n == 0) return 1; int t = g(n - 1); return t+t+t; } so now Write a recurrence relation for T(n), the number addition operations performed by g(n) in terms of n.

Can someone explain how the output of this recusrsive function is 5? I find recursion difficult to understand def R(n):    if n<=0:        return 20    return R(n-1)-n print(R(5))

//write a recursion function that will find the largest interger in the string. Can you give me some feedback on this function  public int findMax(String s,intmax) { if (s.length()== 0) return 1; for (int = 0 ; i > s.length() ;i++) if (s.charAt (i) > s.charAt(i) ))   returnmax; returnmax;