BASIC STOICHIOMETRY T01/S01 Based on the balanced equation, Molar Mass (g/mol) P4 + 502 - P4010 P4 02 P4010 Avogadro's No. 6.022x1023 mol"1 123.90 calculate the molecules of 02 required when 93 molecules of P4010 are formed. 32.000 283.89 exact number, no tolerance Question Attempts: 0 of 1 used SUBMIT ANSWER SAVE FOR LATER LIMITING REAGENTS T02/S22 Based on the balanced equation Molar Mass (g/mol) 2NBr3 + 3NaoH - N2 + 3NaBr + зновг NB13 253.72 calculate the number of of excess reagent units remaining when 104 NBR3 molecules and 147 NaOH 39.997 NAOH formula units react? N2 28.013 NaBr НOBr Avogadro's No. 6.022x1023 mol"1 102.800 96.911 exact number, no tolerance Question Attempts: 0 of 1 used SUBMIT ANSWER SAVE FOR LATER

Chemistry: Principles and Reactions
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Author:William L. Masterton, Cecile N. Hurley
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Chapter3: Mass Relations In Chemistry; Stoichiometry
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Problem 54QAP: Ammonia reacts with a limited amount of oxygen according to the equation...
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BASIC STOICHIOMETRY T01/S01
Based on the balanced equation,
Molar Mass (g/mol)
P4 + 502 - P4010
P4
02
P4010
Avogadro's No.
6.022x1023 mol"1
123.90
calculate the molecules of 02 required when 93 molecules of P4010 are formed.
32.000
283.89
exact number, no tolerance
Question Attempts: 0 of 1 used
SUBMIT ANSWER
SAVE FOR LATER
Transcribed Image Text:BASIC STOICHIOMETRY T01/S01 Based on the balanced equation, Molar Mass (g/mol) P4 + 502 - P4010 P4 02 P4010 Avogadro's No. 6.022x1023 mol"1 123.90 calculate the molecules of 02 required when 93 molecules of P4010 are formed. 32.000 283.89 exact number, no tolerance Question Attempts: 0 of 1 used SUBMIT ANSWER SAVE FOR LATER
LIMITING REAGENTS T02/S22
Based on the balanced equation
Molar Mass (g/mol)
2NBr3 + 3NaoH - N2 + 3NaBr + зновг
NB13
253.72
calculate the number of of excess reagent units remaining when 104 NBR3 molecules and 147 NaOH
39.997
NAOH
formula units react?
N2
28.013
NaBr
НOBr
Avogadro's No.
6.022x1023 mol"1
102.800
96.911
exact number, no tolerance
Question Attempts: 0 of 1 used
SUBMIT ANSWER
SAVE FOR LATER
Transcribed Image Text:LIMITING REAGENTS T02/S22 Based on the balanced equation Molar Mass (g/mol) 2NBr3 + 3NaoH - N2 + 3NaBr + зновг NB13 253.72 calculate the number of of excess reagent units remaining when 104 NBR3 molecules and 147 NaOH 39.997 NAOH formula units react? N2 28.013 NaBr НOBr Avogadro's No. 6.022x1023 mol"1 102.800 96.911 exact number, no tolerance Question Attempts: 0 of 1 used SUBMIT ANSWER SAVE FOR LATER
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