Based on the coordinate system, determine the internal normal force, shear force, and moment at(1) 1m from A(2) 4m from A(3) 6m from A(4) 8m from A And(5) What is the insight? ### Analysis of Beam Loading and ReactionsIn the given diagram, a beam is subjected to various forces and moments. Understanding the loading conditions is crucial for determining the reactions at supports and the internal forces throughout the beam.#### Support and Beam Layout:- **Point A**: The left end of the beam, with a support (roller support).- **Point B**: The right end of the beam, with a support (roller support).- **Length of sections**: - From A to the start of the distributed load: 2 meters - Length of the distributed load: 3 meters - From the end of the distributed load to the location of the moment: 2 meters - From the location of the moment to B: 2 meters- **Total length of the beam**: 9 meters#### Loads and Moments Applied:- **Uniformly Distributed Load (UDL)**: - Location: Between 2 meters and 5 meters from point A - Magnitude: 800 N/m (Newtons per meter)- **Moment**: - Location: 7 meters from point A - Magnitude: 4.2 kN·m (kilonewton-meters) - Direction: Clockwise### Explaining Elements:1. **Uniformly Distributed Load (UDL)**: - A UDL is spread evenly along a portion of the beam. - The total load exerted by the UDL = Load per unit length x Length of load = 800 N/m x 3 m = 2400 N (or 2.4 kN). - This load acts downward.2. **Moment**: - A moment is a force causing rotational effect. - Here, located at 7 meters from A, the moment is 4.2 kN·m, creating a clockwise rotation.### Reaction Calculation:To maintain static equilibrium (i.e., the beam doesn’t move), the sum of vertical forces and moments around any point must be zero. Therefore, by analyzing the forces and moments:1. **Sum of Vertical Forces**: - Let \(R_A\) and \(R_B\) be the vertical reactions at supports A and B respectively. - Equation: \(R_A + R_B - 2.4 \text{ kN} = 0\) (since the only vertical loads

Hi! Thank you for the question, As per the honor code, we are allowed to answer three sub-parts at a…

Answered: Based on the coordinate system,…

Based on the coordinate system, determine the internal normal force, shear force, and moment at (1) 1m from A (2) 4m from A (3) 6m from A (4) 8m from A And (5) What is the insight?

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Problem Set 1 5 kN/m Solve the following problems. Show complete solutions and appropriate diagrams.…

Q: 2-69. Determine the magnitude and coordinate direction angles of the resultant force, and sketch…

Q: For the building frame shown, analyze them using the Portal method. Show computations for the shears…

Q: 1. Formulas and Common values for Reduction factor for the ultimate moment (ϕ). 2. Describe why or…

A: A steel structure is a metal structure comprised of structural steel* components that link to bear…

Q: Draw the shear and bending moment diagram of the beam shown. Submit a picture or scanned copy of…

Q: Which of the following is true sign convention for shear forces while calculating from the right…

A: Answer is Option D Upward Force is Negative and Downward is Positive Trick To Learn Use Word RUN RUN…

Q: Develop the Shear and Momentum equations for the segments (AB and BC). Make sure you include the…

A: Work to be done: Develop the Shear and Momentum equations for the segments (AB and BC).

Q: 1. Shear and Moment Diagram: F2 kN F1 kN/m F3 kN/m B E 1 m 3 m 2 m 3 m Shear Equation Moment…

Q: Determine the magnitude of the resultant force and its direction measured counterclockwise from the…

Q: calculate the magnitudes of shear force and bending moment at each point by using shear-moment…

A: Support Reactions : Taking moment about A, ∑MA = 0RE×6 - 17×1 - 15×2 - 45 - 25×6×9 - 12×30×5×12 +…

Q: Instructions: Draw the shear and bending moment diagram of each beam loaded as shown. Show your…

Q: 22 kN/m 14.67 kN/m 4 m. 10 m.

Q: M C 题3.9图题3.10 图 M M B

Q: beams are loaded and supported as shown in the accompanying figure: Draw complete shear and moment…

Q: Q1: If F-150 lb and @= 55, determine the magnitude and direction measured clockwise from the…

A: Resultant Force(FR)= 160.71 lb Angle(θ)= 38.34 degree

Q: Sketch the shear and bending moment diagrams for the beams below, indicating values of shear force…

Q: Find shear and bending moment diagram and draw its elastic curve. Show your complete solution. 6…

A: For simplicity assume that the origin is at the right support of the beam. Derive equations of Shear…

Q: Develop the Shear and Momentum equations for the segments (AB and BC). Make sure you include the…

Q: Instructions: For each problem show your solutions clearly and orderly with a sketch off its free-…

Q: 4) Determine the resultant force and specify where it acts on the beam measured from A. Provide a…

A: Consider the free body diagram of the given beam as shown below. Consider the summation of external…

Q: Draw shear force and bending moment diagrams for the given simply supported beam.

A: Draw a free body diagram converting the UDL into a point loadAs UDL is given 5kn and it is acting on…

Q: 1. Express the resultant force acting on the hook in cartesian vector and find the coordinate…

A: Given Data:F1=500lbF2=800lbHorizontal Angle= θ1=30°Vertical Angle =θ2=45°

Q: Sketch the following forces on the x, y, z coordinate axes. Show a, β, γ. a) F = {50i + 60j - 10k}…

Q: For the beams loaded as shown below: (a) Determine the bending moments at each of the supports (b)…

Q: Draw the shear and bending moment diagrams by developing the equations for shear and bending moment…

A: Civil engineering structural design is an extremely competent field. It may be defined as a…

Q: Replace the 400N force by 1) a force through A and a couple whose forces act vertically through D…

A: Solution: Given: Force = 400 N couples: A couple is defined as a two parallel forces that have the…

Q: X- direction 17KN 17KN 30KNM 25KNM An

A: The given overhanging beam is analyzed by using the equation of equilibrium equations. The…

Q: Construct the shear and moment equations of the beams shown below, and draw the shear and moment…

Q: Draw the shear-force and bending-moment diagrams for the beam shown. PROVIDE A DETAILED AND COMPLETE…

A: Given:- To find:- Shear force and bending moment diagram

Q: Express each of the forces in Cartesian vector form and determine the magnitude and coordinate…

Q: Problem Set 4 |1100 lb 400 lb/ft Ho 1. For the beam shown, derive the expressions 6000 lb/ft B for V…

A: Given data:

Q: Use cantilever method to estimate the forces in the laterally loaded frame shown. Loads: fifth…

A: Solution: Analyse the frame using cantilever Method: Point of contraflexure occurs at the middle…

Q: Given three ropes of the following magnitudes, F1= 195 lb., F2= 75 lb., and F3= 50 lb., determine…

A: 3 ropes are connected from point A. Force on rope AB = F1 = 195lb Force on rope AC = F2 = 75lb Force…

Q: For the simply supported beam subjected to the loading shown, derive equations for the shear force V…

A: The given simply supported beam is analyzed by using the equation of equilibrium equations: The…

Q: 2.5 kips 500lb A 12" 500 cm 200 am

A: Note: Hi! Thank you for the question, As per the honour code, we are allowed to answer three…

Q: calculate the magnitudes of shear force and bending moment at each point by using shear-moment…

A: Question is based on overhang beam subjected to point load, bracket load, uniform load and varying…

Q: 400 N 40 35 300 N 25 20

Q: what location (measured from A) does the maximum moment occur? Enter your answer in meters, using…

A: Location for positive that is sagging moment is 1.292m form a but for maximum bending moment…

Q: 800 N/m 4.2 kN-m A В 2 m 3 m 2 m 2 m

Q: Determine the magnitude and direction of force, F, from the given force triangle, if the resultant…

Q: Calculate bending moments and shear forces for the following cantilevers and supported timber beams.…

Q: Determine magnitude of the moment of force F about the line OB given that F = 340 N, a = 295 mm, b =…

Q: A. Force System 1. Determine the components of the 500N force directed up to the right as shown in…

Q: nd the magnitude and sense of the moment of the 60-lb force about points A and B

A: a) Moment about point A:- By using Pythagoras Theorem, Hypotenuse=122+402=41.76mm Now,…

Q: Problem 1 Find the magnitude of the resultant force and the coordinate direction angles. 1900 N 900…

Q: 100KN 20 kN/m 140KN-m 2m 2m 2m 4m 110 kN 70 kN

A: End Reaction forces are given 110kN and 70kN for the left end and right end respectively. Now, we…

Q: Derive the expressions for V and M and draw the shear force and bending moment diagrams. Neglect the…

A: Hi there!! it seems there is two questions so, we are going to answer the first question as the…

Q: of shear and moment

Q: Draw the shear, bending moment, and axial force diagrams and the qualitative deflected shape for the…

Q: Construct the shear and moment equations of the beams shown below, and draw the shear and moment…

Concept explainers

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.

Question

Based on the coordinate system, determine the internal normal force, shear force, and moment at

(1) 1m from A

(2) 4m from A

(3) 6m from A

(4) 8m from A

And

(5) What is the insight?

### Analysis of Beam Loading and Reactions

In the given diagram, a beam is subjected to various forces and moments. Understanding the loading conditions is crucial for determining the reactions at supports and the internal forces throughout the beam.

#### Support and Beam Layout:
- **Point A**: The left end of the beam, with a support (roller support).
- **Point B**: The right end of the beam, with a support (roller support).
- **Length of sections**:
- From A to the start of the distributed load: 2 meters
- Length of the distributed load: 3 meters
- From the end of the distributed load to the location of the moment: 2 meters
- From the location of the moment to B: 2 meters
- **Total length of the beam**: 9 meters

#### Loads and Moments Applied:
- **Uniformly Distributed Load (UDL)**:
- Location: Between 2 meters and 5 meters from point A
- Magnitude: 800 N/m (Newtons per meter)

- **Moment**:
- Location: 7 meters from point A
- Magnitude: 4.2 kN·m (kilonewton-meters)
- Direction: Clockwise

### Explaining Elements:
1. **Uniformly Distributed Load (UDL)**:
- A UDL is spread evenly along a portion of the beam.
- The total load exerted by the UDL = Load per unit length x Length of load = 800 N/m x 3 m = 2400 N (or 2.4 kN).
- This load acts downward.

2. **Moment**:
- A moment is a force causing rotational effect.
- Here, located at 7 meters from A, the moment is 4.2 kN·m, creating a clockwise rotation.

### Reaction Calculation:
To maintain static equilibrium (i.e., the beam doesn’t move), the sum of vertical forces and moments around any point must be zero. Therefore, by analyzing the forces and moments:

1. **Sum of Vertical Forces**:
- Let \(R_A\) and \(R_B\) be the vertical reactions at supports A and B respectively.
- Equation: \(R_A + R_B - 2.4 \text{ kN} = 0\) (since the only vertical loads

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step 5

Step 6

Step 7

Step 8

Step 9

Step 10

Step by step

Solved in 10 steps with 19 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

The geometry of the truss that you are to analyze is shown below in Figure 1. The load at joint B is at an unknown angle 0 from the horizontal as shown. The following data is known: Three-member simple truss Joint-to-joint length of member AC: Magnitude of force F applied at joint B: A LYX Fixed support at joint A Rolling support (y movement arrested) at joint C 0° ≤ 0 ≤ 360° 30° B Ө 45° F 0.6 meters 550 Newtons с Figure 1: Three bar truss with applied force F at angle 0 counterclockwise from horizontal For a given angle 0 in degrees your task is to determine the tensions in members AB, BC, and AC, as well as reaction forces Ax, Ay, and Cy. The convention used here is that members in compression will have a negative value for their tension, and reaction forces are aligned with the positive x- and y-axes.
Learning Goal: To learn to apply the method of joints to a truss in a systematic way and thereby find the loading in each member of the truss. In analyzing or designing trusses, it is necessary to determine the force in each member of the truss. One way to do this is the method of joints. The method of joints is based on the fact that if the entire truss is in equilibrium, each joint in the truss must also be in equilibrium (i.e., the free-body diagram of each joint must be balanced). Consider the truss shown in the diagram. The applied forces are P₁ = 630 lb and P₂ = 410 lb and the distance is d = 8.50 ft. (Figure 1) Figure A E 30° B D 30° d C 1 of 1 Part D - The Forces in the Members at Joint D Having found FCD in the analysis of joint C, there are now only two unknown forces acting on joint D. Determine the two unknown forces on joint D. Express the magnitudes of the forces to three significant figures. Separate your answers with a comma. FDB =, Submit FDE = Submit Part E - The…
Learning Goal: To learn to apply the method of joints to a truss in a systematic way and thereby find the loading in each member of the truss. In analyzing or designing trusses, it is necessary to determine the force in each member of the truss. One way to do this is the method of joints. The method of joints is based on the fact that if the entire truss is in equilibrium, each joint in the truss must also be in equilibrium (i.e.. the free- body diagram of each joint must be balanced). Consider the truss shown in the diagram. The applied forces are P₁ = 630 lb and P₂ = 330 lb and the distance is d = 8.50 ft. (Figure 1) Figure E 30⁰ d B D P₁ 30° d с P₂ Part A - Where to Start the Analysis For this truss, what joint is the best place to start the analysis? Select the correct answer. O Joint A O Joint B Joint C O Joint D O Joint E Submit Previous Answers ✓ Correct Because joint C is the only one that has both a known force and at most two unknown forces, we have to begin the analysis…
The rigid bar BDE is supported by two links AB and CD. Link AB is made of aluminum (E = 70 GPa) and has a cross-sectional area of 519 mm2; link CE is made of steel (E = 200 GPa) and has a cross-sectional area of 619 mm?. For the 41 kN force shown, determine the deflection of B (mm) *deflection should have a negative sign if compression and positive if tension. Also, your final answer should have two decimal places 04 m 0.3 m E 0.4 m 0.2 m
Zero-Force Members are structural members that support No loading but aid in the stability of the truss. Tips on getting the zero-force members: 1. there is no external load or reaction at that joint 2. Insufficient structural members to satisfy or "balance" the system: Summation of forces along the horizontal and vertical 3. two of the members are collinear As shown in the figure, structural members of zero-force members can be noticed through observation. At a glance, it can be inferred that the member FG and FE are zero force members, because: First, there is no external load applied on the joint Secondly, taking the Joint F, if Summation of Forces along horizontal = 0 is executed, only the member FG has the horizontal component, or the "ability" to "balance" the system, and if Summation of Forces along vertical = 0 is executed, the member FE has the vertical component, or the "ability" to "balance" the system only. Aside from members FG and FE, through observation, determine the…
a) create a free body diagram of the truss and determine the external forces at the supports b) isolate joint a (method of joints) c) isolate joint c (method of joints) d) isolate joint d (method of joints) e) check results by isolating joint b (method of joints) f) summarize your results in a force diagram
The system of forces in the belt shown can be reduced into a single force at O and a couple. Find the single force
The rigid bar BDE is supported by two links AB and CD. Link AB is made of aluminum (E = 70 GPa) and has a cross-sectional area of 519 mm2; link CE is made of steel (E = 200 GPa) and has a cross-sectional area of 633 mm2. For the 36 kN force shown, determine the deflection of B (mm) *deflection should have a negative sign if compression and positive if tension. Also, your final answer should have two decimal places
Compute the deformation of the beam using conjugate method E= 200 GPa I= 1000 x 106 mm4
Zero-Force Members are structural members that support No loading but aid in the stability of the truss. Tips on getting the zero-force members: 1. there is no external load or reaction at that joint 2. Insufficient structural members to satisfy or "balance" the system: Summation of forces along the horizontal and vertical 3. two of the members are collinear As shown in the figure, structural members of zero-force members can be noticed through observation. H G F A D E At a glance, it can be inferred that the member FG and FE are zero force members, because: First, there is no external load applied on the joint Secondly, taking the Joint F, if Summation of Forces along horizontal = 0 is executed, only the member FG has the horizontal component, or the "ability" to "balance" the system, and if Summation of Forces = 0 is executed, the member FE has the vertical component, or the "ability" to "balance" the system only. along vertical Aside from members FG and FE, through observation,…
Ch. Ex. 22 - Stresses and deformations in statically determinate structures; members of trusses and simple frames 1 out of 3 attempts Do not round intermediate calculations. Give your final answer(s) to three significant figures. For the steel truss (E = 29 × 106 psi) and loading shown, determine the deformations of the members BD and DE, knowing that their cross-sectional areas are3 in² and 4 in², respectively. SBD= & DE 20 kips 7 ft 20 kips 7 ft 20 kips 7 ft x 10-³ in. x 10 ³ in. B D 15 ft E Assistance Check My Work View Hint View Question Practice This Question Print Question Help Report a Problem
Structural mechanics 'method I used was portal method how do I solve for the following what are the shear in column bf,lp what is the moment at the ends of column ko and ei what is the moment at the right end of beam kl what is the moment at the left end beam fg what is the shear in beam fg