Base on the image provided below, write down a pair of equivalent mnemonic opcode/operand instructions that best describes the register indirect addressing mode. Remember that the data is distributed according to the Little Endian format. REGISTER INDIRECT ADDRESSING MEMORY Data Address EAX 34 12 3412 34 02002 EBX 10 00 1000H 2000H 12 02000 1B 020FE A2 020FC DS 0100 X10 01000H AB 01000 100 O a. MOV AX, [Bx] or MOV AX, DS:[BX] Ob. MOV AX, [CX] or MOV AX, DS:[CX] o. MOV AX, [BX] or MOV AX, [DS:BX] n4. MOV AX, [BX] or MOV AX, SS:[BX]

Write an assembly code to assign the register BX with 4014H, and register DX with 4028 H. Move the content of BX to DX, und verse versa. Then, copy the now value of low content for BX and DX .to memory location [2131 H], and [2139H]

True or false

20 LDA 50 21 SUB 51 50 100 51 200 Choose the contents of the registers: PC, MAR, MDR, IR, A at the end of fetch-execute cycle for instruction 20: PC MAR MDR IR A