Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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Bar stock of initial diameter = 90 mm is drawn with a draft = 15 mm. The draw die has an entrance angle = 18°, and the coefficient of friction at the work‑die interface = 0.08. The metal behaves as a perfectly plastic material with yield stress = 105 MPa. Determine (a) area reduction, (b) draw stress, (c) draw force required for the operation, and (d) power to perform the operation if exit velocity = 1.0 m/min
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- A wire is drawn through a draw die with an entry angle = 15o. The starting diameter is 0.100 in. And the final diameter = 0.080 in. The coefficient of friction at the work-given interface = 0.07. The metal has a coefficient of resistance K = 30,000 psi and a strain hardening exponent of n = 0.20. Determine the stretching force and the stretching force in this operation.arrow_forwardA cold rolling operation is to be used to reduce a 50 mm thick and 200 mm wide copper plate. The entering velocity of the plate is 15 m/min and the exit velocity is 18 m/min. The coefficient of friction is 0.2 and assuming that the reduction in thickness during this process is the maximum draft permissible. If the plate widens by 5% after rolling, calculate the power required to drive the rolls. Assume average flow stress of the material as 180 MPa.arrow_forwardNonearrow_forward
- A sheet 300mm wide 25mm thick with two drives, each with a radius of 250mmit is passed through a rolling stand with rollers. Work is thickness in one layer at 50 rpm roll speed 22reduced to mm. The work material has a yield curve determined by K = 275 MPa and n = 0.15.The friction coefficient between the rollers and the work is considered to be 0.12. Successful rolling of frictionDetermine if it is sufficient to allow its operation. If it is sufficient;a) Rolling force,b) Momentc) Calculate the power.arrow_forwardQuestion 3 A rolling operation on a 250 mm wide, 8 mm thick, 1112 cold rolled steel takes place using hardened steel rolls with a surface finish of 0.03 um. The rolls have a diameter of 350 mm and rotates at 115 rpm. The final thickness of the plate is 6 mm and the entry speed of the plate is 1.8 m/s. Calculate: 3.1 The minimum coefficient of friction required, that will make the rolling operation possible. 3.2 The required roll force. 3.3 The position of the neutral point, xn 3.4 Indicate, using a sketch, the neutral point showing all relevant notation and dimensions.arrow_forwardCalculate (1) die pressure distribution and (2) forging force for plane strain forging (open die forging). Assume yield strength of the material is Y, and yielding criterion is von Mises. ho 2Lo h Forged to 2L xdx L 'x+value Note: Assume Zo Constant Plane strain Die pressure distribution h L L Die pressure distribution h MATERIAL L dx -(-1) Friction Hill Y L When 0; =Y P=Y' = Calculate forging force X L dF elemental volume Average pressurearrow_forward
- Maximum reduction in thickness for one pass in rolling process is Ahmas that can be expressed by Ah = u'R, where u is coefficient between contact surfaces and R is roller radius. Then, angle subtended by the deformation zone for u =0.1 (in degree) is friction maxarrow_forwardA small connecting rod is forged from AISI 1015 steel at 1200oC. Calculate the forging force in a mechanical press at a speed of 200 mm / s when the die comes into contact with the part. The volume of the connecting rod is estimated to be 28680 mm3, and 20% of the starting material is expected to burn off as flash (flash). In the final form the projected area is 3500 mm2 without flash. The width of the flash is 7.6mm around 300mm in circumference.arrow_forwardUsing average pressure formulas and ignoring barrelling, plot the force (vertical axis) versus reduction-in-height (horizontal axis is *100) curve in open-die forging of a cylindrical, annealed copper specimen whose height is 1 in and diameter is 1 in, from reduction-in-height of 0% to 75%, when the friction between the flat dies and the specimen ho-h ho is a) μ = 0 b) μ c) μ = 0.1 0.2arrow_forward
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